Question

我试图根据性别生成一个随机的名字和姓氏，并填入表格。我正在使用角度$http，而且我对角度很新。每次加载

时都会出现此错误

 Use of undefined constant firstName - assumed 'firstName'

我的观点：

 @section('content')
 <form ng-app="getNameApp" ng-controller="getNameController">

   Male<input type="radio" ng-model="gender" value="male" name="gender" /><br />
   Female<input type="radio" ng-model="gender" value="female" name="gender" /><br />

   <input type="text" ng-model="{{ firstName }}" name="firstName" />
   <input type="text" ng-if="{{ lastName }}" value="{{ lastName.body }}" name="lastName" />

   <button ng-click="randomNameController()">Randomize</button>
</form>
@stop

我的JS

angular.module('getNameApp', [])
.controller('getNameController', getNameController);

function getNameController ($scope, $http) {
   $scope.gender = 'male';

   var randomName = $http({
       url: '/randomName',
       method: "GET",
       params: {gender: $scope.gender}
   });

   randomName.success(function(data) {
       $scope.firstName = data.firstName;
       $scope.lastName = data.lastName;
   });
   randomName.error(function() {
       document.write(randomName);
   });

}

我的控制器

 public function randomName () {
    $faker = Faker\Factory::create();
    $gender = Input::get('gender');

    if ($gender == 'male') {
        $names = [
            'firstName' => $faker->firstNameMale
        ];
    } else {
        $names = [
            'firstName' => $faker->firstNameFemale
        ];
    }
    $names['lastName'] = $faker->lastName;
    return $names;
}

编辑：我检查了inspect元素的网络选项卡，并用createCharacter显示500内部服务器错误。（路线到页面）

Answer 1

我没有看到那种错误，但是你有问题，你正试图从承诺中获取firstName

randomName.success(function() {
     $scope.firstName = randomName.firstName; //<-- Here randomName is a promise not data
     $scope.lastName = randomName.lastName;
  });

而是获取作为success回调的第一个参数的数据

 randomName.success(function(data) {
     $scope.firstName = data.firstName; 
     $scope.lastName = data.lastName;
  });

Answer 2

所以看起来这个问题的直接答案是ng-model=""上没有括号。话虽这么说，我的代码中存在很多问题，其工作版本如下。希望它可以帮助有类似问题的人。我知道它不是最干净的。

此代码根据性别创建一个随机生成名称的表单。您可以选择性别并点击随机化以填充其他名称。我正在使用https://github.com/fzaninotto/Faker库生成名称。

查看：

 <form ng-app="getNameApp" ng-controller="getNameController">

  Male<input type="radio" ng-model="gender" value="male" name="gender" /><br />
  Female<input type="radio" ng-model="gender" value="female" name="gender" /><br />

  <input type="text" ng-model="firstName" name="firstName" />
  <input type="text" ng-model="lastName" name="lastName" />

  <button ng-click="generate(gender)">Randomize</button>
</form>

JS：

 angular.module('getNameApp', []).controller('getNameController', getNameController);

function getNameController（$ scope，$ http）{ $ scope.gender =＆＃39;男性＆＃39 ;;

$scope.generate = function (gender) {
    var randomName = $http({
        url: '/randomName',
        method: "GET",
        params: {gender: gender}
    });

    randomName.success(function (data) {
        var names = {
            firstName: data.firstName,
            lastName: data.lastName
        };
        $scope.firstName = names.firstName;
        $scope.lastName = names.lastName;

    });
    randomName.error(function () {
        document.write(randomName);
    });
    return $scope;

};

   $scope.generate($scope.gender);
}

控制器：

public function randomName () {
    $faker = Faker\Factory::create();
    $gender = Input::get('gender');

    if ($gender == 'male') {
        $names = [
            'firstName' => $faker->firstNameMale
        ];
    } else if ($gender == 'female') {
        $names = [
            'firstName' => $faker->firstNameFemale
        ];
    }
    $names['lastName'] = $faker->lastName;
    return $names;
}

使用带角度的未定义常量

2 个答案: