根据我在互联网上阅读的内容,Y值是亮度值,可用于创建灰度图像。以下链接:http://www.bobpowell.net/grayscale.htm,在计算位图图像的亮度时有一些C#代码:
{
Bitmap bm = new Bitmap(source.Width,source.Height);
for(int y=0;y<bm.Height;y++) public Bitmap ConvertToGrayscale(Bitmap source)
{
for(int x=0;x<bm.Width;x++)
{
Color c=source.GetPixel(x,y);
int luma = (int)(c.R*0.3 + c.G*0.59+ c.B*0.11);
bm.SetPixel(x,y,Color.FromArgb(luma,luma,luma));
}
}
return bm;
}
我有一个返回YUV值并在字节数组中包含Y数据的方法。我有当前的一段代码,它在Marshal.Copy上失败 - 试图读取或写入受保护的内存。
public Bitmap ConvertToGrayscale2(byte[] yuvData, int width, int height)
{
Bitmap bmp;
IntPtr blue = IntPtr.Zero;
int inputOffSet = 0;
long[] pixels = new long[width * height];
try
{
for (int y = 0; y < height; y++)
{
int outputOffSet = y * width;
for (int x = 0; x < width; x++)
{
int grey = yuvData[inputOffSet + x] & 0xff;
unchecked
{
pixels[outputOffSet + x] = UINT_Constant | (grey * INT_Constant);
}
}
inputOffSet += width;
}
blue = Marshal.AllocCoTaskMem(pixels.Length);
Marshal.Copy(pixels, 0, blue, pixels.Length); // fails here : Attempted to read or write protected memory
bmp = new Bitmap(width, height, width, PixelFormat.Format24bppRgb, blue);
}
catch (Exception)
{
throw;
}
finally
{
if (blue != IntPtr.Zero)
{
Marshal.FreeHGlobal(blue);
blue = IntPtr.Zero;
}
}
return bmp;
}
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答案 0 :(得分:2)
我认为你已经分配了像素。长度字节,但是正在复制像素。长度长,这是内存的8倍(长是64位或8位)字节大小)。
你可以尝试:
blue = Marshal.AllocCoTaskMem(Marshal.SizeOf(pixels[0]) * pixels.Length);
您可能还需要在Bitmap构造函数中使用int []作为像素和PixelFormat.Format32bppRgb(因为它们都是32位)。使用long []可以获得每像素64位,这不是24位像素格式所期望的。
你可能最终会得到蓝色而不是灰色 - 取决于你的UINT_Constant和INT_Constant的值是什么。
没有必要做“&amp; 0xff”,因为yuvData []已经包含一个字节。
答案 1 :(得分:1)
以下是您可以尝试的另外两种方法。
public Bitmap ConvertToGrayScale(byte[] yData, int width, int height)
{
// 3 * width bytes per scanline, rounded up to a multiple of 4 bytes
int stride = 4 * (int)Math.Ceiling(3 * width / 4.0);
byte[] pixels = new byte[stride * height];
for (int y = 0; y < height; y++)
{
for (int x = 0; x < width; x++)
{
byte grey = yData[y * width + x];
pixels[y * stride + 3 * x] = grey;
pixels[y * stride + 3 * x + 1] = grey;
pixels[y * stride + 3 * x + 2] = grey;
}
}
IntPtr pixelsPtr = Marshal.AllocCoTaskMem(pixels.Length);
try
{
Marshal.Copy(pixels, 0, pixelsPtr, pixels.Length);
Bitmap bitmap = new Bitmap(
width,
height,
stride,
PixelFormat.Format24bppRgb,
pixelsPtr);
return bitmap;
}
finally
{
Marshal.FreeHGlobal(pixelsPtr);
}
}
public Bitmap ConvertToGrayScale(byte[] yData, int width, int height)
{
// 3 * width bytes per scanline, rounded up to a multiple of 4 bytes
int stride = 4 * (int)Math.Ceiling(3 * width / 4.0);
IntPtr pixelsPtr = Marshal.AllocCoTaskMem(stride * height);
try
{
for (int y = 0; y < height; y++)
{
for (int x = 0; x < width; x++)
{
byte grey = yData[y * width + x];
Marshal.WriteByte(pixelsPtr, y * stride + 3 * x, grey);
Marshal.WriteByte(pixelsPtr, y * stride + 3 * x + 1, grey);
Marshal.WriteByte(pixelsPtr, y * stride + 3 * x + 2, grey);
}
}
Bitmap bitmap = new Bitmap(
width,
height,
stride,
PixelFormat.Format24bppRgb,
pixelsPtr);
return bitmap;
}
finally
{
Marshal.FreeHGlobal(pixelsPtr);
}
}
答案 2 :(得分:0)
如果我使用此代码,我会在左上角看到一个带有几个像素的黑色图像,这在运行时是稳定的:
public static Bitmap ToGrayscale(byte[] yData, int width, int height)
{
Bitmap bm = new Bitmap(width, height, PixelFormat.Format32bppRgb);
Rectangle dimension = new Rectangle(0, 0, bm.Width, bm.Height);
BitmapData picData = bm.LockBits(dimension, ImageLockMode.ReadWrite, bm.PixelFormat);
IntPtr pixelStateAddress = picData.Scan0;
int stride = 4 * (int)Math.Ceiling(3 * width / 4.0);
byte[] pixels = new byte[stride * height];
try
{
for (int y = 0; y < height; y++)
{
for (int x = 0; x < width; x++)
{
byte grey = yData[y * width + x];
pixels[y * stride + 3 * x] = grey;
pixels[y * stride + 3 * x + 1] = grey;
pixels[y * stride + 3 * x + 2] = grey;
}
}
Marshal.Copy(pixels, 0, pixelStateAddress, pixels.Length);
bm.UnlockBits(picData);
}
catch (Exception)
{
throw;
}
return bm;
}