Question

有没有办法可以获得每个月的总计。我看过Rollup，但似乎无法弄明白。

我的查询是

SELECT t.city,f.fname,f.lname,
SUM(CASE datepart(month,ddate) WHEN 1 THEN 1 ELSE 0 END) AS 'January',
SUM(CASE datepart(month,ddate) WHEN 2 THEN 1 ELSE 0 END) AS 'February',
SUM(CASE datepart(month,ddate) WHEN 3 THEN 1 ELSE 0 END) AS 'March',
SUM(CASE datepart(month,ddate) WHEN 4 THEN 1 ELSE 0 END) AS 'April',
SUM(CASE datepart(month,ddate) WHEN 5 THEN 1 ELSE 0 END) AS 'May',
SUM(CASE datepart(month,ddate) WHEN 6 THEN 1 ELSE 0 END) AS 'June',
SUM(CASE datepart(month,ddate) WHEN 7 THEN 1 ELSE 0 END) AS 'July',
SUM(CASE datepart(month,ddate) WHEN 8 THEN 1 ELSE 0 END) AS 'August',
SUM(CASE datepart(month,ddate) WHEN 9 THEN 1 ELSE 0 END) AS 'September',
SUM(CASE datepart(month,ddate) WHEN 10 THEN 1 ELSE 0 END) AS 'October',
SUM(CASE datepart(month,ddate) WHEN 11 THEN 1 ELSE 0 END) AS 'November',
SUM(CASE datepart(month,ddate) WHEN 12 THEN 1 ELSE 0 END) AS 'December',
SUM(CASE datepart(year,ddate) WHEN 2014 THEN 1 ELSE 0 END) AS 'TOTAL'
from  world T 
INNER JOIN sales F  ON T.ID=F.ID
where t.city = ROME 
group by t.city,f.fname,f.lname

输出示例

t.city,       f.fname,   f.lname    January  total
ROME           John       Doe         5       5 
Grand Total                           5       5

Answer 1

你试过这个吗？

group by GROUPING SETS((t.city, f.fname, f.lname), ())

要获得Grand Total，您还需要更改select。

并且，作为注释：仅对字符串和日期常量使用单引号。将它们用于列标识符可能会导致混淆和问题。要么完全删除引号，要么使用方括号或双引号。

编辑：

没有group by扩展名或CTE，这是一种痛苦。只需极少的修改就可以做到这一点：

SELECT (case when which = 'normal' then t.city else 'Grand Total' end),
       (case when which = 'normal' then f.fname end),
       (case when which = 'normal' then f.lname end),
SUM(CASE datepart(month,ddate) WHEN 1 THEN 1 ELSE 0 END) AS 'January',
SUM(CASE datepart(month,ddate) WHEN 2 THEN 1 ELSE 0 END) AS 'February',
SUM(CASE datepart(month,ddate) WHEN 3 THEN 1 ELSE 0 END) AS 'March',
SUM(CASE datepart(month,ddate) WHEN 4 THEN 1 ELSE 0 END) AS 'April',
SUM(CASE datepart(month,ddate) WHEN 5 THEN 1 ELSE 0 END) AS 'May',
SUM(CASE datepart(month,ddate) WHEN 6 THEN 1 ELSE 0 END) AS 'June',
SUM(CASE datepart(month,ddate) WHEN 7 THEN 1 ELSE 0 END) AS 'July',
SUM(CASE datepart(month,ddate) WHEN 8 THEN 1 ELSE 0 END) AS 'August',
SUM(CASE datepart(month,ddate) WHEN 9 THEN 1 ELSE 0 END) AS 'September',
SUM(CASE datepart(month,ddate) WHEN 10 THEN 1 ELSE 0 END) AS 'October',
SUM(CASE datepart(month,ddate) WHEN 11 THEN 1 ELSE 0 END) AS 'November',
SUM(CASE datepart(month,ddate) WHEN 12 THEN 1 ELSE 0 END) AS 'December',
SUM(CASE datepart(year,ddate) WHEN 2014 THEN 1 ELSE 0 END) AS 'TOTAL'
from  world T INNER JOIN
      sales F
      ON T.ID=F.ID cross join
      (select 'normal' as which union all select 'total') as which
where t.city = ROME 
group by (case when which = 'normal' then t.city else 'Grand Total' end),
         (case when which = 'normal' then f.fname end),
         (case when which = 'normal' then f.lname end);

（我没有重新格式化查询的其余部分，但是你不应该为列标识符使用单引号。只对字符串和日期常量使用单引号。）

Answer 2

编辑：使用GROUP BY ROLLUP（分组列），这将计算聚合列的总和。默认情况下，它将返回＆＃39; NULL＆＃39;对于所有分组列，但您可以放置一个ISNULL包装来摆脱它，或返回一个特定的值。

SELECT ISNULL(t.city, 'Grand Total') AS [City],f.fname AS [Fname],f.lname AS [Lname],
  SUM(CASE datepart(month,ddate) WHEN 1 THEN 1 ELSE 0 END) AS [January],
  SUM(CASE datepart(month,ddate) WHEN 2 THEN 1 ELSE 0 END) AS [February],
  SUM(CASE datepart(month,ddate) WHEN 3 THEN 1 ELSE 0 END) AS [March],
  SUM(CASE datepart(month,ddate) WHEN 4 THEN 1 ELSE 0 END) AS [April],
  SUM(CASE datepart(month,ddate) WHEN 5 THEN 1 ELSE 0 END) AS [May],
  SUM(CASE datepart(month,ddate) WHEN 6 THEN 1 ELSE 0 END) AS [June],
  SUM(CASE datepart(month,ddate) WHEN 7 THEN 1 ELSE 0 END) AS [July],
  SUM(CASE datepart(month,ddate) WHEN 8 THEN 1 ELSE 0 END) AS [August],
  SUM(CASE datepart(month,ddate) WHEN 9 THEN 1 ELSE 0 END) AS [September],
  SUM(CASE datepart(month,ddate) WHEN 10 THEN 1 ELSE 0 END) AS [October],
  SUM(CASE datepart(month,ddate) WHEN 11 THEN 1 ELSE 0 END) AS [November],
  SUM(CASE datepart(month,ddate) WHEN 12 THEN 1 ELSE 0 END) AS [December],
  SUM(CASE datepart(year,ddate) WHEN 2014 THEN 1 ELSE 0 END) AS [TOTAL]
FROM  world T 
   INNER JOIN sales F  ON T.ID=F.ID
WHERE t.city = ROME 
GROUP BY ROLLUP(t.city,f.fname,f.lname)

SQL Grand Total的最后一行

2 个答案: