Question

例如，我有以下表格数据：

    Date          branch     sale     profit
    Jan 1, 2014    A         10          5
    Jan 2, 2014    A         11          6
    Jan 3, 2014    A         20          9
    Feb 1, 2014    A         11          4
    Feb 2, 2014    B         20          10
    Feb 3, 2014    C         12          6
    Mar 1, 2014    A         25          15
    Mar 2, 2014    B         60          30
    Mar 3, 2014    B         40          20

我已按月成功对这些数据进行分组，并将销售额和利润相加。请参阅下面的我的SQL查询。

SELECT DATE_FORMAT(date,'%b') as date, SUM(sale) as sale, SUM(profit) as profit FROM sales_report GROUP BY MONTH(date) ORDER BY MONTH(date)

我的结果值低于

Date    branch     sale     profit
Jan      A         41          20
Feb      A         43          20
Mar      A         125         65

我想在这里实现的是选择具有最新日期的分支并按升序保留月份我还想添加字段来计算分支。我希望这些结果如下。请帮忙

Date    branch     sale     profit   Count
Jan      A         41          20      1
Feb      C         43          20      3
Mar      B         125         65      2

Answer 1

我认为你想要count(distinct)作为计数栏。对于分支，您可以使用group_concat() / substring_index()：

SELECT year(date), month(date),
       substring_index(group_concat(branch order by date desc), ',', 1) as last_branch,
       SUM(sale) as sale, SUM(profit) as profit,
       count(distinct branch) as NumBranches
FROM sales_report
GROUP BY year(date), month(date)
ORDER BY min(date);

SQL Query for Group by有两个排序值并计算相等的值

1 个答案: