SQL Query for Group by有两个排序值并计算相等的值

Question

例如，我有以下表格数据：

    Date          branch     sale     profit
    Jan 1, 2014    A         10          5
    Jan 2, 2014    A         11          6
    Jan 3, 2014    A         20          9
    Feb 1, 2014    A         11          4
    Feb 2, 2014    B         20          10
    Feb 3, 2014    C         12          6
    Mar 1, 2014    A         25          15
    Mar 2, 2014    B         60          30
    Mar 3, 2014    B         40          20

我已按月成功对这些数据进行分组，并将销售额和利润相加。 请参阅下面的我的SQL查询。

SELECT DATE_FORMAT(date,'%b') as date, SUM(sale) as sale, SUM(profit) as profit FROM sales_report GROUP BY MONTH(date) ORDER BY MONTH(date)

我的结果值低于

Date    branch     sale     profit
Jan      A         41          20
Feb      A         43          20
Mar      A         125         65

我想在这里实现的是选择具有最新日期的分支并按升序保留月份 我还想添加字段来计算分支。我希望这些结果如下。请帮忙

Date    branch     sale     profit   Count
Jan      A         41          20      1
Feb      C         43          20      3
Mar      B         125         65      2

Answer 1

我认为你想要count(distinct)作为计数栏。对于分支，您可以使用group_concat() / substring_index()：

SELECT year(date), month(date),
       substring_index(group_concat(branch order by date desc), ',', 1) as last_branch,
       SUM(sale) as sale, SUM(profit) as profit,
       count(distinct branch) as NumBranches
FROM sales_report
GROUP BY year(date), month(date)
ORDER BY min(date);