Question

我有一个查询，基本上是按天分组总和

SELECT CountDate, SUM(Max_Count) as MaximumCount, SUM(Min_Count) as MinimumCount
FROM countTable
WHERE countId IN ('48', '34', '65', '63', '31', '64', '86') 
AND CountDate BETWEEN '2014-08-14' AND '2014-08-16' 
GROUP BY CountDate 
ORDER BY CountDate

输出结果为

 Date       | Maximum   |  Minimum
------------|-----------|----------------------
2014-08-14  |  3018234  |  3014212
2014-08-15  |  3023049  |  3018510
2014-08-16  |  3026813  |  3023244

我希望查询能够获得最后一天的MaximumCount与第一天的MinimumCount之间的差异。

查询结果应为最后一天的最大值，即2014-08-16：3026813减去（ - ）第一天的最小值，即2014-08-14 | 3014212.因此3026813 - 3014212

任何帮助我如何实现这一点将非常感激。

Answer 1

SELECT 
 (SELECT [Maximum] FROM TABLE WHERE Date = (SELECT MAX(Date) FROM TABLE)) -
 (SELECT [Minimum] FROM TABLE WHERE Date = (SELECT MIN(Date) FROM TABLE))
FROM TABLE

Answer 2

我认为这是正确的。

DECLARE @STARTDATE DATE = '2014-08-14'
DECLARE @ENDDATE DATE = '2014-08-16'

SELECT  A.CountDate,
        B.MaximumCount - A.MinimumCount
FROM    (
SELECT  CountDate, 
        SUM(Max_Count) AS MaximumCount, 
        SUM(Min_Count) AS MinimumCount,
FROM    countTable
WHERE   countId IN ('48','34','65','63','31','64','86') 
AND     CountDate BETWEEN @STARTDATE AND  @ENDDATE
GROUP   BY CountDate) A
LEFT JOIN (
SELECT  DATEADD(DAY,CountDate,1) CountDate
        SUM(Max_Count) AS MaximumCount, 
        SUM(Min_Count) AS MinimumCount,
FROM    countTable
WHERE   countId IN ('48','34','65','63','31','64','86') 
AND     CountDate BETWEEN BETWEEN @STARTDATE AND  @ENDDATE 
GROUP   BY DATEADD(DAY,CountDate,1)) B

ON      A.CountDate = B.CountDate

Answer 3

参考Jithin Shaji的回答，我已经得到了这个查询的结果

DECLARE @STARTDATE DATE = '2014-08-14'
DECLARE @ENDDATE DATE = '2014-08-16'
DECLARE @NOOFDAYS INT = datediff(day, @STARTDATE, @ENDDATE)

 SELECT  A.CountDate,
    A.MaximumCount - B.MinimumCount AS CountSum
 FROM    (
 SELECT  CountDate, 
    SUM(Max_Count) AS MaximumCount, 
    SUM(Min_Count) AS MinimumCount
 FROM    countTable
 WHERE   countId IN ('48','34','65','63','31','64','86') 
 AND     CountDate BETWEEN @STARTDATE AND  @ENDDATE
 GROUP   BY CountDate) A
 LEFT JOIN (
 SELECT  DATEADD(DAY, @NOOFDAYS, CountDate) AS CountDate,
    SUM(Max_Count) AS MaximumCount, 
    SUM(Min_Count) AS MinimumCount
 FROM    countTable
 WHERE   countId IN ('48','34','65','63','31','64','86') 
 AND     CountDate BETWEEN @STARTDATE AND @ENDDATE 
 GROUP   BY DATEADD(DAY, @NOOFDAYS, CountDate)) B

 ON      A.CountDate = B.CountDate

用于获取两个日期之间差异的SQL语句

3 个答案: