我有一个代码用外部div包装帖子上的每个图像(当悬停在图像上时用于共享按钮)。 问题是,当我想写the_permalink();在function.php中,它被包装在a href标签中的'或'中。
这导致共享链接看起来像这样:
https://plus.google.com/share?url=%3C?php%20the_permalink();%20?%3E
这是function.php中的代码:
function breezer_addDivToImage( $content ) {
// A regular expression of what to look for.
$pattern = '/(<img([^>]*)>)/i';
// What to replace it with. $1 refers to the content in the first 'capture group', in parentheses above
$the_url = the_permalink();
$replacement = '<div class="imgWrap">
$1
<div class="imgDescription">
<div class="theShareLinks">
<img src="http://localhost/mySite/wp-content/uploads/2014/08/dfc2.png" />
<a href="http://twitter.com/share?text=&url=<?php the_permalink(); ?>" class="img-twitter" title="Share on Twitter"></a>
<a href="http://www.facebook.com/sharer.php?u=<?php the_permalink(); ?>?" title="Share on Facebook" onclick="window.open(this.href, \'newwin\', \'width=500, height=200\'); return false;" class="img-facebook"></a>
<a href="https://plus.google.com/share?url=<?php the_permalink(); ?>" class="img-google" title="Share on Google"></a>
</div>
</div>
</div>';
// run preg_replace() on the $content
$content = preg_replace( $pattern, $replacement, $content );
// return the processed content
return $content;
}
add_filter( 'the_content', 'breezer_addDivToImage' );
以上代码中的行包含在“”:
中<a href="http://twitter.com/share?text=&url=<?php the_permalink(); ?>" class="img-twitter" title="Share on Twitter"></a>
<a href="http://www.facebook.com/sharer.php?u=<?php the_permalink(); ?>?" title="Share on Facebook" onclick="window.open(this.href, \'newwin\', \'width=500, height=200\'); return false;" class="img-facebook"></a>
<a href="https://plus.google.com/share?url=<?php the_permalink(); ?>" class="img-google" title="Share on Google"></a>
答案 0 :(得分:1)
更改:
<a href="http://twitter.com/share?text=&url=<?php the_permalink(); ?>" class="img-twitter" title="Share on Twitter"></a>
到
<a href="http://twitter.com/share?text=&url='.get_the_permalink() .'" class="img-twitter" title="Share on Twitter"></a>
应该有效。