成功进行Ajax调用后更新客户端信息

时间:2014-08-20 17:00:31

标签: javascript jquery asp.net asp.net-mvc-3 asp.net-ajax

我有一个页面,每当状态发生变化时我都在做Ajax Post。我想更新模型以反映新的变化。例如,如果状态从AZ更改为NY,我想将状态更改为NY,将学生名字更改为Jenny。但是,表格没有更新。我做错了什么?

历史:以前,我将信息保存在数据库中,每次有人访问该页面时,我都必须多次调用数据库。然后,我将其切换到会话变量,我必须创建几个变量并维护这些变量。我正在寻找一种更好的方法。我认为做Ajax帖子并且能够在成功发布后更新表单会更加清晰,至少在我看来。

以下是我的代码示例:

@model School.Models.NewStudents

@{
    ViewBag.Title = "New Students";
}

<link href="@Url.Content("~/Content/Site.css")" rel="stylesheet" type="text/css" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.js" type="text/javascript"></script>

<script type="text/javascript">
   function changeState() {
      var Students= $('#NewStudent').serialize();
        $.ajax({
            url: '@Url.Action("SetNewStudents", "Student")',
             type: 'POST',
             datatype:'json',
             data: Students,
             cache: false,
             // contentType: 'application/text;charset=UTF-8',
             success: function (e) {
             //Here is where I am updating the form with the new NewStudents Object.
                  $('#NewStudent').html(e.NewStudents); 
             }
</script>



@using (Html.BeginForm("SetNewStudents", "Student", FormMethod.Post, new {id = "NewStudent" }))
{
     @Html.ValidationSummary(true)
    @Html.LabelFor(model => model.FirstName, "FirstName:")
            <br/>
            @Html.EditorFor(model => model.FirstName)
            @Html.ValidationMessageFor(model => model.FirstName)
    @Html.DropDownList("Name", null, "Choose State", new {  onchange = "changeState()" })
 }   



 [HttpPost]
 public JsonResult SetNewStudents(NewStudents NewStudents)
  {
     NewStudents.FirstName = "Jenny"; //I changed the first name To Jenny now. However, the form is not updated to show Jenny.
     return Json(new { success =true, NewStudents = NewStudents  });
  }     

更新:我更改了方法以返回JSON Result而不是View。

这是URL编码的请求: 姓= sdfsd&安培;名称= 15

这是JSON响应: 返回结果:{“ok”:true,“NewStudent”:{“FirstName”:“Jenny”,“StateID”:15}}

1 个答案:

答案 0 :(得分:1)

在你的AJAX成功函数中,你返回的是JSON,而不是html,所以这行不能正常工作

$('#NewStudent').html(e.NewStudents);

您需要提取值然后更新每个元素,例如

success: function (e) {
  $('#FirstName').val(e.NewStudent.FirstName);
  $('#StateID').val(e.NewStudent.StateID);
}