点击并双击c#中的事件不起作用

时间:2014-08-20 16:47:37

标签: c# winforms double-click

我的C#应用​​程序中有以下代码

第一个决定用户双击图片时会发生什么。

 private void pictureDoubleClick(Object sender, EventArgs e)
        {
            PictureBox picture = (PictureBox)sender;
            Console.WriteLine(picture.ImageLocation);
            MessageBox.Show("Test");
        }

另一个单击:

private void picutureClick(Object sender, EventArgs e)
        {
            PictureBox picture = (PictureBox)sender;

            if (picture.BorderStyle == BorderStyle.None)
            {
                picture.BorderStyle = BorderStyle.Fixed3D;
                picture.BackColor = Color.Red;
            }
            else
            {
                picture.BorderStyle = BorderStyle.None;
                picture.BackColor = Color.White;
            }
        }

我把这两个函数称为:

box.Click += new System.EventHandler(this.picutureClick);
box.DoubleClick += new System.EventHandler(this.pictureDoubleClick);

但是我遇到了一个奇怪的错误,DoubleClick事件不会被激活,唯一让它工作的方法就是我注释掉单击。无论我是否评论或取消评论Doubleclick事件,单击都有效。我四处寻找解决方案,但我找不到任何解决了我的问题。

2 个答案:

答案 0 :(得分:2)

这是一种奇怪的行为,更改图片框的BorderStyle会阻止点击传播(Click事件将始终在DoubleClick事件之前提升。

我真的不知道如何正确处理它,但我们可以做一些黑客来使功能正常工作。我们可以介绍一个"滞后"在ClickDoubleClick之间,DoubleClick之前会检查Click

我们在这里使用Timer来完成这项工作:

private Timer _timer;
private PictureBox _sender;
private int _clicks;

public Form1()
{
    InitializeComponent();

    pictureBox.Click += picutureClick;
    pictureBox.DoubleClick += (s, e) =>
                                    {
                                        // do your double click handling

                                        _clicks = 0;
                                    };

    // this Interval comes from trail and error, it's a balance between lag and  
    // correctness. To play safe, you can use SystemInformation.DoubleClickTime,
    // but may introduce a bit long lagging after you click and before you
    // see the effects.
    _timer = new Timer {Interval = 75}; 
    _timer.Tick += (s, e) =>
                        {
                            if (_clicks < 2)
                            {
                                ClickHandler(_sender);
                            }

                            _clicks = 0;

                            _timer.Stop();
                        };
}

private void picutureClick(Object sender, EventArgs e)
{
    _clicks++;
    _sender = (PictureBox) sender;

    if (_clicks == 1)
    {
        _timer.Start();
    }
}

private void ClickHandler(PictureBox picture)
{
    if (picture.BorderStyle == BorderStyle.None)
    {
        // this line is not thread safe, but you could comment out the .InvokeIfRequire()
        // and uncomment this line to have a look at your form's behavior
        //picture.BorderStyle = BorderStyle.Fixed3D;
        picture.InvokeIfRequired(c => (c as PictureBox).BorderStyle = BorderStyle.Fixed3D);
        picture.BackColor = Color.Red;
    }
    else
    {
        // same for this
        //picture.BorderStyle = BorderStyle.Fixed3D;
        picture.InvokeIfRequired(c => (c as PictureBox).BorderStyle = BorderStyle.None);
        picture.BackColor = Color.White;
    }
}

在上面的代码中,我使用了一个扩展方法来处理跨线程属性更新:

public static void InvokeIfRequired(this Control c, Action<Control> action)
{
    if (c.InvokeRequired)
    {
        c.Invoke(new Action(() => action(c)));
    }
    else
    {
        action(c);
    }
}

修改

我上面使用的扩展方法是简化为执行跨线程属性更新而编写的代码。有关此主题的更多详细信息,请访问:Automating the InvokeRequired code pattern

以下是扩展方法的一些细节:

扩展方法仅在非泛型非嵌套静态类中声明时才有效。要使其工作,您需要声明一个新的public static class来保存方法。

// your form class declared here
public partial class Form1 : Form
{
    // code omitted here
}

// declare the extension method in this extension class
public static class ControlExtensions
{
    public static void InvokeIfRequired(this Control c, Action<Control> action)
    {
        if (c.InvokeRequired)
        {
            c.Invoke(new Action(() => action(c)));
        }
        else
        {
            action(c);
        }
    }
}

答案 1 :(得分:1)

更改图片框的边框时,您需要重置点击事件。这就是为什么它没有工作,只切换一次点击事件,如果你评论边界的变化,它将开始工作...抱歉,但我不知道为什么会发生这种情况,不知道这是否有用我的信息= /