Question

我编写了一个查询，为这个例子选择了让我们说10 rows。

+-----------+------------+
| STORENAME | COMPLAINTS |
+-----------+------------+
| Store1    |          4 |
| Store7    |          2 |
| Store8    |          1 |
| Store9    |          1 |
| Store2    |          1 |
| Store3    |          1 |
| Store4    |          1 |
| Store5    |          0 |
| Store6    |          0 |
| Store10   |          0 |
+-----------+------------+

我如何显示TOP 3行但将剩余的行roll up放入名为＆＃34;其他＆＃34; ，它将所有Complaints加在一起？

所以像这样：

+-----------+------------+
| STORENAME | COMPLAINTS |
+-----------+------------+
| Store1    |          4 |
| Store7    |          2 |
| Store8    |          1 |
| Other     |          4 |
+-----------+------------+

那么上面发生了什么，是显示top3然后将剩余行的投诉添加到名为other 的行中

我已经耗尽了所有资源，无法找到解决方案。如果这有意义，请告诉我。

我创建了上述表格的SQLfiddle，如果可能的话可以编辑：）

希望这是可能的:)

谢谢，麦克

Answer 1

这样的事可能有效

select *,    row_number() over (order by complaints desc) as sno
into #temp
from
(
SELECT 
  a.StoreName
  ,COUNT(b.StoreID) AS [Complaints]
FROM Stores a
LEFT JOIN 
(
  SELECT 
    StoreName
    ,Complaint
  ,StoreID
  FROM Complaints
  WHERE Complaint = 'yes') b on b.StoreID = a.StoreID


GROUP BY a.StoreName
) as t ORDER BY [Complaints] DESC

select storename,complaints from #temp where sno<4
union all
select 'other',sum(complaints) as complaints from #temp where sno>=4

Answer 2

我使用双重聚合和row_number()执行此操作：

select (case when seqnum <= 3 then storename else 'Other' end) as StoreName,
       sum(numcomplaints) as numcomplaints
from (select c.storename, count(*) as numcomplaints,
             row_number() over (order by count(*) desc) as seqnum
      from complaints c
      where c.complaint = 'Yes'
      group by c.storename
     ) s
group by (case when seqnum <= 3 then storename else 'Other' end) ;

从我所看到的情况来看，您并不需要stores中的任何其他信息，所以此版本只是将该表格保留下来。

将剩余的行汇总到一个名为＆＃34;其他＆＃34;

2 个答案: