Question

我正在尝试将整数数组序列化为XML，但我无法让输出看起来像我想要的那样。我需要找到一些方法来覆盖数组中每个元素的元素名称我到目前为止的代码：

var numbers = new int[]{1, 2, 3, 4, 5};

var serializer = new XmlSerializer(typeof(int[]), new XmlRootAttribute("rows"));
using (var stringWriter = new StringWriter())
{
    serializer.Serialize(stringWriter, numbers);
    Console.Write(stringWriter.ToString());
}

我追求的输出：

<?xml version="1.0" encoding="utf-16"?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <row>1</row>
  <row>2</row>
  <row>3</row>
  <row>4</row>
  <row>5</row>
</rows>

我看到的当前输出：

<?xml version="1.0" encoding="utf-16"?>
<rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <int>1</int>
  <int>2</int>
  <int>3</int>
  <int>4</int>
  <int>5</int>
</rows>

Answer 1

您可以创建一个单独的类来保存您的值，您可以按如下方式指定Xml属性：

[Serializable]
[XmlRoot("rows")]
public class Rows
{
    [XmlElement("row")]
    public List<int> Elements { get; set; } 
}

public static void SerializeOnScreen()
{
    Rows numbers = new Rows();
    numbers.Elements = new List<int>() { 1, 2, 3, 4, 5 };

    var serializer = new XmlSerializer(typeof(Rows));
    using (var stringWriter = new StringWriter())
    {
        serializer.Serialize(stringWriter, numbers);
        Console.Write(stringWriter.ToString());
    }
}

使用覆盖将基元列表序列化为XML

1 个答案: