如何解析两个xml文件并比较java中各个xml的特定元素？

Question

第一个xml文件test_balance1.xml

第二个xml文件test_balance2.xml

如何使用SAX解析器解析两个xml文件并比较java中的特定元素？

Ex：我需要解析

                line 12: <brm:CURRENT_BAL>-30</brm:CURRENT_BAL> 
                line 24: <brm:CURRENT_BAL>0</brm:CURRENT_BAL>  of test_balance1.xml and

                line 12: <brm:CURRENT_BAL>55</brm:CURRENT_BAL> 
                line 24: <brm:CURRENT_BAL>20</brm:CURRENT_BAL> of test_balance2.xml

解析后如何比较特定元素，即CURRENT_BAL = -30和CURRENT_BAL = 55，CURRENT_BAL = 0和CURRENT_BAL = 20

Answer 1

您可以在此处使用XMLUtils +参考答案：Best way to compare 2 XML documents in Java

import oracle.xml.diff.XmlUtils;
import oracle.xml.diff.Options;

import java.io.File;

import org.w3c.dom.Node;
import org.w3c.dom.Document;

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;

public class textDiff
{
    public static void main(String[] args) throws Exception
    {
        XmlUtils xmlUtils = new XmlUtils();

        //Parse the two input files
        DocumentBuilderFactory dbFactory =   
                  DocumentBuilderFactory.newInstance();
        dbFactory.setNamespaceAware(true);
        DocumentBuilder docBuilder = 
                  dbFactory.newDocumentBuilder();
        Node doc = docBuilder.parse(new File(args[0]));
        Node doc1 = docBuilder.parse(new File(args[1]));

        //Run the diff
        try
        {
            Document diffAsDom = xmlUtils.diffToDoc(doc, 
                                  doc1, new Options());
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
    }
}