Question

大家好，我有两个看起来像这样的阵列：

array(3) {
  ["15PCW"]=>
  array(4) {
    ["longitude"]=>
    string(17) "-88.3511517556820"
    ["latitude"]=>
    string(16) "35.9298720640290"
    ["knownLocationTag"]=>
    string(7) "15PCW"
    ["count"]=>
    string(1) "0"
  }
  ["12RCD"]=>
  array(4) {
    ["longitude"]=>
    string(17) "-88.4423244521810"
    ["latitude"]=>
    string(16) "34.0964334531290"
    ["knownLocationTag"]=>
    string(6) "12RCD"
    ["count"]=>
    string(1) "0"
  }
  ["43RICK"]=>
  array(4) {
    ["longitude"]=>
    string(17) "-88.5154700586220"
    ["latitude"]=>
    string(16) "34.0726750453080"
    ["knownLocationTag"]=>
    string(11) "43RICK"
    ["count"]=>
    string(1) "0"
  }
}


array(3) {
  [12]=>
  array(4) {
    ["entryID"]=>
    string(2) "12"
    ["longitude"]=>
    string(17) "-88.35108453430"
    ["latitude"]=>
    string(16) "32.9298345948310"
    ["knownLocationTag"]=>
    NULL
  }
  [13]=>
  array(4) {
    ["entryID"]=>
    string(2) "13"
    ["longitude"]=>
    string(17) "-88.3513437005120"
    ["latitude"]=>
    string(16) "32.9458453856350"
    ["knownLocationTag"]=>
    NULL
  }
  [14]=>
  array(4) {
    ["entryID"]=>
    string(2) "14"
    ["longitude"]=>
    string(17) "-88.3511544967700"
    ["latitude"]=>
    string(16) "32.9293468765800"
    ["knownLocationTag"]=>
    NULL
  }
}

我想使用PHP迭代每个第二组数组并运行一个函数，包括来自两个数组的数据（在这种情况下，我们检查两个GPS位置之间的距离），如果它们在x英里的范围内第一个数组中列表中的项目增加“计数”值，或者如果它们超出该设置范围，则将该值添加到第一个数组中。

到目前为止，我的解决方案只是4个嵌套的foreach循环，它变得很乱。这是正确的方法还是有更好的方法？

foreach ($devices as $devicesKey => $devicesValue)
{
    foreach ($devicesValue as $devicesKey2 => $devicesValue2)
    {
        $testarray[$devicesKey2] = $devicesValue2;
    }
    foreach ($locations as $locationsKey => $locationsValue)
{
    foreach ($locationsValue as $locationsKey2 => $locationsValue2)
    {
        $testarray2[$locationsKey2] = $locationsValue2;
    }
}
    $test =  distance($testarray['longitude'],$testarray['latitude'],$testarray2['longitude'],$testarray2['latitude']);
    if ($test < .26)
    {
        //we would incriment the counter here since we match
    }
    else
    {
        //we would add the value to the array here since we are outside the bounds
    }
}

Answer 1

看起来很乱，它可能是正确的方法。您可以通过创建evaluateDevice函数来清理代码，对于第二个列表中的每个元素，您将其传递给函数，该函数负责根据您的第一个列表处理它

foreach($devices as  $key => $outerDevice){
    foreach($outerDevice as $device){
        evaluateDevice($outerDevice, $device, $key);
    }
}

function evaluateDevice(array $outerDevice, array $device, $key)
{
    foreach($locations as $outerLocation){
        foreach($OuterLocation as $location){
            $distance = distance($device['longitude'], $device['latitude'], $location['longitude'], $location['latitude']);

            if($distance < .26){
                // increment count
            }else{
                // remove from second list and add to first
                $locations['12ABC"] = $device;
                unset($outerDevice[$key]);
            }
        }
    }
}

迭代通过两个嵌套数组在php中进行数据比较

1 个答案: