Question

我正在编写一个MVC Web应用程序，并且一些JavaScript文件实际上只需要“包含”在特定视图中。

使用以下代码检索我需要的包项目列表：

        HttpContext currentHttpContext = HttpContext.Current;
        var httpContext = new HttpContextWrapper(currentHttpContext);

        BundleContext bundlecontext = new BundleContext(httpContext, BundleTable.Bundles, "~/bundles/");

        bundlecontext.EnableInstrumentation = false;

        var bundleList = bundlecontext.BundleCollection.ToList().Where(b => b.Path.StartsWith("~/bundles/" + HttpContext.Current.Request.RequestContext.RouteData.Values["controller"].ToString().ToLower() + "_"));

输出每个文件的内容，或只是执行＆lt; script src =“[file]”＆gt;＆lt; / script＆gt;但是，我想要输出的内容与Script.Render（）输出的内容相同：

＆lt; script src =“/ bundles / bootstrap？v = 2Fz3B0iizV2NnnamQFrx-NbYJNTFeBJ2GM05SilbtQU1”＆gt;＆lt; / script＆gt;

是否可以通过编程方式执行此操作？

Answer 1

＆＃39; ave想出了这一点，在查看了MVC的源代码后，我可以看到你可以使用Scripts.Render ......从开始就应该是显而易见的＆gt;＆lt;

    public static IHtmlString RenderScripts()
    {

        List<string> bundlePaths = new List<string>();
        HttpContext currentHttpContext = HttpContext.Current;
        var httpContext = new HttpContextWrapper(currentHttpContext);

        BundleContext bundlecontext = new BundleContext(httpContext, BundleTable.Bundles, "~/bundles/");

        bundlecontext.EnableInstrumentation = false;

        var bundleList = bundlecontext.BundleCollection.ToList().Where(b => b.Path.StartsWith("~/bundles/" + HttpContext.Current.Request.RequestContext.RouteData.Values["controller"].ToString().ToLower() + "_"));

        foreach (Bundle bundleItem in bundleList)
        {
            bundlePaths.Add(bundleItem.Path);
        }

        return Scripts.Render(bundlePaths.ToArray());
    }

重现Script.Render（）以在MVC中输出特定于视图的脚本

1 个答案: