我有一个UITextField
,因为我应该只能输入整数(没有文本),之后必须将整数值传递给NSMutableDictionary
。然后从这本词典中我必须发布到网络服务器。
答案 0 :(得分:3)
将UITextField
的键盘类型更改为数字键盘,这样只需要数字:
[textField setKeyboardType:UIKeyboardTypeNumberPad];
您还可以检查输入的文本是否为数字:
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
if (string.length == 0 || [NSScanner scanInt:string]) {
return YES;
}
return NO;
}
您可以使用以下代码将值保存在字典中:
//if you want to save as number
[myDictionary setObject:[NSNumber numberWithInt:[textField.text intValue] forKey:@"YourKey"];
OR
//if you want to save as string
[myDictionary setObject:textField.text forKey:@"YourKey"];
答案 1 :(得分:3)
//创建文本字段
txt = [[UITextField alloc] initWithFrame:CGRectMake(100, 10, 150, 50)];
txt.placeholder = @"enter here";
txt.borderStyle = UITextBorderStyleRoundedRect;
txt.autocorrectionType = UITextAutocorrectionTypeNo;
[txt setClearButtonMode:UITextFieldViewModeWhileEditing];
[txt setKeyboardType:UIKeyboardTypeNumberPad];
txt.delegate=self;
[cell.contentView addSubview:txt];
您可以检查输入的文字是否为数字:
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
NSString *newString = [Height.text stringByReplacingCharactersInRange:range withString:string];
if([newString length] > 3)
{
UIAlertView *obj_AlertView=[[UIAlertView alloc]initWithTitle:@""
message:@"Enter 3 digit only"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[obj_AlertView show];
}
return !([newString length] > 3);
}
现在在你的按钮动作中创建一个NSMutabledictionary来发布
-(IBAction)btnClicked:(id)sender
{
UIButton *button = (UIButton *)sender;
button.tintColor=[UIColor redColor];
NSLog(@"%@",button);
NSMutableDictionary *datadict=[NSMutableDictionary dictionary];
现在将您的textfield值传递给nsmutabledictionary以发布
if (txt.text !=NULL) {
[datadict setValue:[NSNumber numberWithInt:[txt.text intValue]] forKey:@"txt"];
// [datadict setObject:[NSString stringWithFormat:@"%@",txt.text] forKey:@"txt"]; (if it is for NSdictionary)
} 其他 {
[datadict setObject:[NSString stringWithFormat:@" "] forKey:@"txt"];
}
现在将值发布到web-server
NSData* jsonData = [NSJSONSerialization dataWithJSONObject:datadict options:kNilOptions error:nil];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
NSURL *someURLSetBefore =[NSURL URLWithString:@" your post web-server link here"];
[request setURL:someURLSetBefore];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setHTTPBody:jsonData];
NSError *error;
NSURLResponse *response;
NSData *responseData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString * string1=[[NSString alloc]initWithData:responseData encoding:NSUTF8StringEncoding];
NSLog(@"%@",string1);
答案 2 :(得分:2)
你可以尝试这样的事情 1.将textField'键盘类型'设置为数字键盘。
2.
NSMutableDictionary *dict=[[NSMutableDictionary alloc]init];
[dict setValue:[NSNumber numberWithInt:[textField.text intValue]] forKey:@"Key"];
希望它有所帮助。
答案 3 :(得分:0)
这是执行此类操作的最佳方式,在 NSString类别中创建以下行,并根据需要检查验证。
-(NSString *)isTextFieldHasNumberOnly
{
NSString *strMessage;
NSString *enteredText=[self trimWhiteSpace];
if ([enteredText length]==0)
{
strMessage=@"Please enter number.";
return strMessage;
}
NSString *numbEx = @"^([0-9]+)?(\\.([0-9]{1,2})?)?$";
NSRegularExpression *numbRegEx = [NSRegularExpression regularExpressionWithPattern:numbEx options:NSRegularExpressionCaseInsensitive error:nil];
NSUInteger numberOfMatches = [numbRegEx numberOfMatchesInString:enteredText options:0 range:NSMakeRange(0, [enteredText length])];
if (numberOfMatches == 0)
strMessage=@"Please enter valid number.";
else
strMessage=@"";
return strMessage;
}