Question

下面是存储在会话中的数组。它工作得很好。

$_SESSION['cart'][$sum_1]=array('car_id'=>$car_id,'location'=>$location,'dropoff'=>$d_location,'date_value'=>$date_value,'date_value_2'=>$date_value_2,'total_days'=>$total_days,'addon'=>$addon);
?>

我这样打电话给他们，

 foreach($_SESSION['cart'] as $total=>$id)
 {
    echo $total;
    echo $id['addon'];
 }

现在我想在上面的数组中添加另一个数组，以包含date_from和date_to 插件项目（$id['addon']）。

我该如何做，然后根据addon_id打电话给他们？这是暂时在数组中存储插件项ID的部分：

'addon'=>$addon

EDITED

$_SESSION['cart'][$sum_1]=array('car_id'=>$car_id,'location'=>$location,'dropoff'=>$d_location,'date_value'=>$date_value,'date_value_2'=>$date_value_2,'total_days'=>$total_days,'addon'=>$addon,array('d_from'=>$date_from,'d_to'=>$date_to))

Answer 1

 foreach($_SESSION['cart'] as $total=>$id)
 {
    echo $total;
    foreach( $id['addon'] as $key=>$value)
    {   
       echo "$key - $value";
    }
 }

我认为日期已经在$ addon中了。如果不是，您只需将变量添加到您已有的数组中，例如

$_SESSION['cart'][$sum_1]=array('car_id'=>$car_id,'location'=>$location,'dropoff'=>$d_location,'date_value'=>$date_value,'date_value_2'=>$date_value_2,'total_days'=>$total_days,'addon'=>$addon,'dates'=> array('d_from'=>$date_from,'d_to'=>$date_to))

或

$dates = array('d_from'=>$date_from,'d_to'=>$date_to);
$_SESSION['cart'][$sum_1]=array('car_id'=>$car_id,'location'=>$location,'dropoff'=>$d_location,'date_value'=>$date_value,'date_value_2'=>$date_value_2,'total_days'=>$total_days,'addon'=>$addon,'dates'=> $dates)

在这种情况下，您必须在第一个代码示例中将'addon'替换为'dates'。

Answer 2

这将为您提供所需的输出

foreach($_SESSION['cart'] as $total=>$id)
{
  if ($id['addon'] == $wanted_addon_to_add_dates) {
    $array['date_from'] = $date_from;
    $array['date_to'] = $date_to;
    $id[(whatever your want here)] = $array;
  }
}

只是建议让你的代码更有意义。它将为您提供类似

的数组

array ('var'=>value, ..., array ('addon'=>addon_id, 'date_from'=>date_from, 'date_to'=>date_to))

foreach($_SESSION['cart'] as $total=>$id)
{
  if ($id['addon'] == $wanted_addon_to_add_dates) {
    $array['date_from'] = $date_from;
    $array['date_to'] = $date_to;
    $array['addon'] = $id['addon'];
    $id['addon'] = $array;
  }
}

如何在数组内添加数组并将其调出

2 个答案: