Question

我的Rest Client有问题。 我的服务

@POST
@Path("/post")
@Consumes("text/plain")
public Response getNumber(String a){
    return Response.status(201).entity("Number is: "+a.toString()).build();
}

我的客户

   try{
        URL url = new URL("http://localhost:8080/RESTform/core/take/post");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "text/plain");
        String input = "123";
        OutputStream os = conn.getOutputStream();
        os.write(input.getBytes());
        os.flush();
        if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
            throw new RuntimeException("Failed : HTTP error code : "
                + conn.getResponseCode());
        }
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));
        String output;
        System.out.println("Output from Server .... \n");
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }
        conn.disconnect();
    }
    catch(MalformedURLException e){}
    catch(IOException e){}

我的路径是：ProjectName / core / take / post 在Eclipse中的服务器上调试之后，我收到一条消息：

输入状态报告，消息方法不允许， description对于请求的资源，不允许使用指定的HTTP方法。 Tomcat 8.0.9

请帮帮我:(

Answer 1

我只将jersey 1.9版本提供的jar（全部）包含在我的库中。

这是REST服务：

import javax.ws.rs.Consumes; import javax.ws.rs.GET; import javax.ws.rs.POST; import javax.ws.rs.Path; import javax.ws.rs.Produces; import javax.ws.rs.core.MediaType; import javax.ws.rs.core.Response; @Path("/hello")

public class HelloWorld {

@POST
@Path("/post")
@Consumes("text/plain")
public Response getNumber(String a){
    return Response.status(201).entity("Number is: "+a.toString()).build();
}
}

以下是其他客户：import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStream; import java.net.HttpURLConnection; import java.net.MalformedURLException; import java.net.URL;

public class Test {
public static void main(String[] args) {

    try {
        URL url = new URL("http://localhost:5050/REST-simple/rest-simple/hello/post");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "text/plain");
        String input = "123";
        OutputStream os = conn.getOutputStream();
        os.write(input.getBytes());
        os.flush();
        if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
            throw new RuntimeException("Failed : HTTP error code : "
                    + conn.getResponseCode());
        }
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));
        String output;
        System.out.println("Output from Server .... \n");
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }
        conn.disconnect();
    } catch (MalformedURLException e) {
    } catch (IOException e) {
    }
}}

试试这个你应该得到输出。

使用POST方法的RESTful Java客户端

1 个答案: