Question

我有一个Apex类（SalesForce中的一个类），可以调用REST Web服务。

public class WebServiceCallout 
{
    @future (callout=true)
    public static void sendNotification(String aStr) 
    {
        HttpRequest req = new HttpRequest();
        HttpResponse res = new HttpResponse();
        Http http = new Http();

        req.setEndpoint('http://xx.xxx.xxx.xx:41000/TestService/web/test');
        req.setMethod('POST');
        req.setHeader('Content-Type', 'application/json');
        req.setBody(aStr); // I want to read this in the web service

        try 
        {
            res = http.send(req);
        } 
        catch(System.CalloutException e) 
        {
            System.debug('Callout error: '+ e);
            System.debug(res.toString());
        }
    }
}

REST Web服务（C＃，WCF）如下所示：

public interface ITestService
{
    [OperationContract]
    [WebInvoke(Method = "POST",
     ResponseFormat = WebMessageFormat.Json,
     BodyStyle = WebMessageBodyStyle.Bare,
     UriTemplate = "/test")]
    string Test(string aStr);
}

Test()方法执行基本操作。

当我跑步时

WebServiceCallout.sendNotification("a test message")

POST进入网络服务，但我怎样才能阅读{strong> HttpRequest req的正文中设置的内容{1}}方法 - sendNotification()？

那就是req.setBody(aStr);的参数应该是什么？

我是否需要在string Test(string aStr);或WebInvoke（例如App.config）中指定其他内容，例如任何配置/属性？

Answer 1

如果要读取传入请求的原始主体，则应将参数类型定义为Stream，而不是string。下面的代码显示了实现您的方案的一种方法，http://blogs.msdn.com/b/carlosfigueira/archive/2008/04/17/wcf-raw-programming-model-receiving-arbitrary-data.aspx上的帖子提供了有关此内容的更多信息＆＃34; raw＆＃34;模式。

public class StackOverflow_25377059
{
    [ServiceContract]
    public interface ITestService
    {
        [OperationContract]
        [WebInvoke(Method = "POST",
         ResponseFormat = WebMessageFormat.Json,
         BodyStyle = WebMessageBodyStyle.Bare,
         UriTemplate = "/test")]
        string Test(Stream body);
    }

    public class Service : ITestService
    {
        public string Test(Stream body)
        {
            return new StreamReader(body).ReadToEnd();
        }
    }

    class RawMapper : WebContentTypeMapper
    {
        public override WebContentFormat GetMessageFormatForContentType(string contentType)
        {
            return WebContentFormat.Raw;
        }
    }

    public static void Test()
    {
        var baseAddress = "http://" + Environment.MachineName + ":8000/Service";
        var host = new ServiceHost(typeof(Service), new Uri(baseAddress));
        var binding = new WebHttpBinding { ContentTypeMapper = new RawMapper() };
        host.AddServiceEndpoint(typeof(ITestService), binding, "").Behaviors.Add(new WebHttpBehavior());
        host.Open();
        Console.WriteLine("Host opened");

        var req = (HttpWebRequest)HttpWebRequest.Create(baseAddress + "/test");
        req.Method = "POST";
        req.ContentType = "application/json";
        var reqStream = req.GetRequestStream();
        var body = "a test message";
        var bodyBytes = new UTF8Encoding(false).GetBytes(body);
        reqStream.Write(bodyBytes, 0, bodyBytes.Length);
        reqStream.Close();
        var resp = (HttpWebResponse)req.GetResponse();
        Console.WriteLine("HTTP/{0} {1} {2}", resp.ProtocolVersion, (int)resp.StatusCode, resp.StatusDescription);
        foreach (var header in resp.Headers.AllKeys)
        {
            Console.WriteLine("{0}: {1}", header, resp.Headers[header]);
        }

        Console.WriteLine();
        Console.WriteLine(new StreamReader(resp.GetResponseStream()).ReadToEnd());
        Console.WriteLine();
    }
}

顺便提一下，您的传入请求在技术上并不正确 - 您说（通过Content-Type）您正在发送JSON，但请求正文（a test message）不是有效的JSON字符串（它应该用引号括起来 - "a test message"代替JSON字符串。）

如何读取HttpRequest的主体发布到REST Web服务 - C＃WCF

1 个答案: