Question

我想将一些样式应用于具有数据属性product的元素，但也应用于特定产品。

有没有办法做这样的事情？

// SASS
[data-product] {
  color: #000;
  &[="red"] {   // <- this line
    color: #f00;
  }
}

Answer 1

在Sass 3.4 之前，这根本不可能。这里的交易破坏功能是将当前选择器存储到变量中的能力以及分割字符串的能力（尽管后者可以通过SassScript函数创建）。

@mixin append-attr($x) {
    $sel: &;
    $collector: ();

    @for $i from 1 through length($sel) {
        $s: nth($sel, $i);
        $last: nth($s, -1);
        @if str-slice($last, -1) == "]" {
            // if is just the bare attribute with no value, $offset will be -1, otherwise it will be -2
            $offset: -1;
            $current-x: $x;

            @if str-slice($last, -2) == '"]' {
                // this attribute already has a value, so we need to adjust the offset
                $offset: -2;
            } @else {
                // no attribute value, so add the equals and quotes
                $current-x: '="' + $x + '"';
            }
            $last: str-slice($last, 1, $offset - 1) + $current-x + str-slice($last, $offset);
            $collector: append($collector, set-nth($s, -1, $last), comma);
        } @else {
            // following line will append $x to your non-attribute selector
            $collector: append($collector, selector-append($s, $x), comma);
            // the following line will not change your non-attribute selector at all
            //$collector: append($collector, $s, comma);
        }
    }

    @at-root #{$collector} {
        @content;
    }
}

用法：

[data-product] {
    color: white;

    @include append-attr("red") {
        color: red;

        @include append-attr('-green') {
            color: green;
        }
    }
}

[one], [two] {
    color: orange;

    @include append-attr('alpha') {
        color: yellow;
    }
}

[test], .test {
    @include append-attr('-one') {
        color: red;
    }
}

.bar input[min] {
    @include append-attr('5') {
        background: yellow;
    }
}

输出：

[data-product] {
  color: white;
}
[data-product="red"] {
  color: red;
}
[data-product="red-green"] {
  color: green;
}

[one], [two] {
  color: orange;
}
[one="alpha"], [two="alpha"] {
  color: yellow;
}

[test="-one"], .test-one {
  color: red;
}

.bar input[min="5"] {
  background: yellow;
}

相关：Modifying the middle of a selector in Sass (adding/removing classes, etc.)

Answer 2

＆＃13;

input[data-product] {
	color: #000;
}
input[data-product=red] {
	color: #f00;
}

＆＃13;

您不需要嵌套，第二种样式将覆盖第一种。

SASS和数据属性选择和嵌套

2 个答案: