从drawable
文件夹中检索图像的最佳方法是什么,而这些图片的名称存储在DB
中,并在listView
中显示?
假设我在drawable
文件夹中有三张图片,其名称存储在DB中:
pic1.jpeg
image2.jpeg
我还有一个名为getAllimages()
的方法,我在其中检索图像名称并将其作为Cursor
从DB返回:
public Cursor getAllImages(){
String sql = "SELECT iId as _id," + COLUMN_IMG_DESC + "," + COLUMN_IMG_NAME + " FROM " + TABLE_NAME";
Cursor cursor = db.rawQuery(sql, null);
if(cursor != null)
cursor.moveToFirst();
return cursor;
}
其中COLUMN_IMG_DESC
是image description
而COLUMN_IMG_NAME
是存储在数据库中的name of the image
然后我有CursorAdapter
我尝试将图片及其描述映射到listView
:
ListView customListView = (ListView)findViewById(R.id.lvCustom);
String[] from = { DatabaseHelper.COLUMN_IMG_DESC, DatabaseHelper.COLUMN_IMG_NAME};
int[] to = {R.id.ivImg, R.id.tvTitle};
SimpleCursorAdapter cursorAdapter = new SimpleCursorAdapter(this, R.layout.custom_listview, cursor, from, to, 0);
cursorAdapter.setViewBinder(new SimpleCursorAdapter.ViewBinder() {
@Override
public boolean setViewValue(View view, Cursor cursor, int columnIndex) {
ImageView imageImageView = (ImageView)findViewById(R.id.ivImg);
String imageValue = cursor.getString(1); //get image names
int[] imgResourceIds = new int[cursor.getColumnCount()]; //initialize array for resource Ids
String images[] = new String[cursor.getColumnCount()]; //initialize an array for image names
for(int i=0; i<cursor.getColumnCount(); i++){
images[i] = imageValue; //store image names to an initialized array
imgResourceIds[i] = getResources().getIdentifier(images[i], "drawable", packageName); //get image name
imageImageView.setImageResource(imgResourceIds[i]); //set image to imageView
}
return true;
}
});
customListView.setAdapter(cursorAdapter);
但我得到了这个结果:我怎么解决这个问题?
提前致谢:)
答案 0 :(得分:0)
您可以通过以下方式使用动态名称从drawable文件夹中获取图像:
resources.getIdentifier(String imageName, String folder, String package);
这将返回一个整数,方法与键入
的方式相同R.drawable.imageName;
如何使用它的一个例子:
Bitmap bitmap[] = new Bitmap[5];
for (int i = 0; i < 5; i++)
bitmap[i] = BitmapFactory.decodeResource(
resources,
resources.getIdentifier("pic" +i, "drawable", "com.example.com")));
这可以从&#34; pic0.png&#34;,&#34; pic1.png&#34; ......直到&#34; pic4.png&#34;当然你可以按你想要的方式自定义
答案 1 :(得分:0)
int[] resID = new int[2]
String[] mDrawableName=new String[2];
mDrawableName[0] = "pic1";
mDrawableName[1] = "image";
mDrawableName[2] = "another_image";
for(i=0:i<=2:i++)
int resID[i] = getResources().getIdentifier(mDrawableName[i] , "drawable", getPackageName());
用法
image.setImageResource(resID[0]);
答案 2 :(得分:0)
好的问题是我分配了适配器布局参数错误。而不是 ListView_Row 我指的是 ListView 本身
所以:
SimpleCursorAdapter cursorAdapter = new SimpleCursorAdapter(this, R.layout.custom_listview, cursor, from, to, 0);
将是:
SimpleCursorAdapter cursorAdapter = new SimpleCursorAdapter(this, R.layout.custom_listview_row, cursor, from, to, 0);