如何在Java中使用Maya日历?
答案 0 :(得分:6)
你的日历现在用完了吗? : - )
答案 1 :(得分:1)
在Java中使用其他日历/年表的最佳方法是优秀的Joda-Time库。它本身没有玛雅年表,但你可以自己实施玛雅规则并将其插入。不应该太繁琐。
答案 2 :(得分:1)
使用JodaTime。哎呀,对不起,在阅读有关java.util.Calendar的问题时只是反射; - )
网上有一些Java applets可能会对您有所帮助。
答案 3 :(得分:1)
如果您真的在寻找解决方案,Maya Calendar implementation看起来非常好。
它使用Java的GregorianCalendar
实现了一个maya Tzolk'in calender。日期可以格里高利语或Tzolk'in格式检索。
以下是核心部分:
[...]
/** parses Date specified in Long Count format, e.g. "12.19.19.17.19" */
public void parseLongCountDate (String longCountDate) {
String [] components = longCountDate.split("\\.");
try {
if (components.length != 5)
throw new Exception("Expecting 5 numbers separated by dots");
int baktuns = Integer.valueOf(components[0]);
int katuns = Integer.valueOf(components[1]);
int tuns = Integer.valueOf(components[2]);
int winals = Integer.valueOf(components[3]);
int kins = Integer.valueOf(components[4]);
set (baktuns, katuns, tuns, winals, kins);
} catch (Throwable e) {
throw new IllegalArgumentException("Invalid long count date format: "
+ e.getMessage());
}
}
/** Set date to given long count date */
public void set (int baktuns, int katuns, int tuns, int uinals, int kins) {
assert MayaTimeUnit.Kin.toDays (1) == 1;
daysSinceGreatCycle =
MayaTimeUnit.Baktun.toDays (baktuns) +
MayaTimeUnit.Katun.toDays(katuns) +
MayaTimeUnit.Tun.toDays(tuns) +
MayaTimeUnit.Winal.toDays(uinals) +
kins;
}
[...]
/** @return day name number in Tzolk'in calendar, e.g. it returns 0 (Ajaw) for the day "4 Ajaw" */
public Tzolkin toTzolkinDayName () {
// The Tzolk'in date is counted forward from 4 Ajaw.
return Tzolkin.DAYS[(daysSinceGreatCycle + 19) % 20]; // relative to Ajaw
}
/** @return day number in Tzolk'in calendar, e.g. it returns 4 for the day "4 Ajaw" */
public int toTzolkinDayNumber () {
// The Tzolk'in date is counted forward from 4 Ajaw.
return (daysSinceGreatCycle + 4) % 13;
}
[...]
/** @return day name number in Haab calendar, e.g. it returns Yaxkin (5) for the day "14 Yaxk'in" */
public Haab toHaabDayName () {
int d = (daysSinceGreatCycle + 349) % 365;
return Haab.DAYS[d / 20];
}
/** @return day number in Haab calendar, e.g. it returns 14 for the day "14 Yaxk'in" */
public int toHaabDayNumber () {
int d = (daysSinceGreatCycle + 349) % 365;
return d % 20 - 1;
}
[...]
/** @return Gregorian calendar representation of currently set date */
public String toGregorianString () {
Calendar c = toGregorianDate ();
return format.format(c.getTime());
}
/** @return Converts currently defined date into Gregorian calendar */
public Calendar toGregorianDate () {
Calendar c = (Calendar)greatCycleStartDate.clone();
c.add(Calendar.DAY_OF_YEAR, daysSinceGreatCycle);
return c;
}
[...]
无论如何:很酷的问题: - )
答案 4 :(得分:0)
LOL, 尝试将最后一个可选日期设为2012年12月21日? 但是它真的没有结束,它刚刚开始,所以你想在2012年12月21日之后再次开始计算?