在数组公式中处理N / A.

Question

我想弄清楚如何在使用数组的公式中处理N/A。我使用Bloomberg数据历史加载项BDH获取最新的EX-DIV日期。但是，如果数组中有N/A，则输出为N/A，而不是最新的EX-DIV日期。

这是我正在使用的公式：

=IF(AN6="","",INDEX(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true"),MATCH(MIN(ABS(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true")-$A$2)),ABS(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true")-$A$2),0)))

• AM6是sedol
• AN6是对数据的检查
• A2是今天的日期

Answer 1

您是否尝试使用IFERROR()封装整个内容？它会变成类似

的东西

=IFERROR(IF(AN6="","",INDEX(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true"),MATCH(MIN(ABS(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true")-$A$2)),ABS(BDS(AM6,"DVD_HIST_ALL","StartCol=2","EndCol=2","array=true")-$A$2),0))),$A$2)