我有一个对象数组[{Date, Count, City}]
让我说我有这个数据
[{01/01/01, 10, New York}, {01/01/01, 15, London}, {01/01/01, 16, Rome},{02/01/01, 40, New York},{02/01/01, 25, London}, {02/01/01, 36, Rome}]
我想使用JQuery填充html表并获得以下结果
Date | New York | London | Rome
01/01/01 | 10 | 15 | 16
02/01/01 | 40 | 25 | 36
是否可以使用JQuery生成与此类似的表?
这是我到目前为止所做的代码
for (var i = 0; i < countResult.length; i++) {
var html = "<table><thead><tr><th>Date</th><th>City</th><th>Count</th></thead><tbody>";
for (var j = 0; j < countResult[i].length; j++) {
html += "<tr>";
html += "<td>" + countResult[i][j].date + "</td><td>" + countResult[i][j].city + "</td><td>" + countResult[i][j].count+ "</td>";
}
html += "</tr>";
html += "</tbody></table></br>";
$(html).appendTo("#div");
}
答案 0 :(得分:1)
我的问题的解决方案是:
var countResult = [
["01/01/01", 10, "New York"],
["01/01/01", 15, "London"],
["01/01/01", 16, "Rome"],
["02/01/01", 40, "New York"],
["02/01/01", 25, "London"],
["02/01/01", 36, "Rome"]
]
var cities = []
$.each(countResult, function(rowNum, row) {
var city = row[2];
if($.inArray(city, cities) < 0) cities.push(city);
});
var html = "<table><thead><tr><th>Date</th>"
+ $.map(cities, function (c) {
return "<th>" + c
}).join("") + "</tr></thead><tbody>";
var summary = {};
$.each(countResult, function
(rowNum, row) {
if(!summary[row[0]]) summary[row[0]] = {}
summary[row[0]][row[2]] = row[1];
});
$.each(summary, function (date, counts) {
html += "<tr><td>" + date;
$.each(counts, function (i, ct) {
html += "<td>" + ct ;
});
html += "</tr>";
});
$(html).appendTo("#div");
答案 1 :(得分:0)
试试此代码
var html='<table>';
var arObj = YOUR ARRAY OBJECT;
$(arObj).each(function(i, u) {
var Date = u[0];
var count = u[1];
var City=u[2];
html=html+'<tr><td>'+Date+'</td><td>'+count+'</td><td>'+City+'</td><td>';
});
html=html+'</table>';
现在附加到html
$('#myDiv').append(html);