Question

我设法编写了以下查询，该查询返回了我需要查看建筑物中楼层占用率和容量的结果。

select 
fma0.bldgcode, 
fma0.floorcode, 
sum(fma0.occ) as Occupancy, 
sum(CASE WHEN FMA0.SPACETYPE like 'A-OFF-%' OR 
    FMA0.SPACETYPE like 'A-WKS-%' THEN FMA0.CAPACITY 
    ELSE 0 END) as Capacity
from fma0 
where fma0.bldgcode = 'tst01' 
group by fma0.bldgcode, fma0.floorcode 
order by fma0.bldgcode, fma0.floorcode

但是我需要添加什么才能获得另一列＆＃34;占用/容量＆＃34;的总和。

THKS

FTD

Answer 1

SELECT 
bldgcode,
floorcode,
Occupancy,
Capacity ,
Occupancy+Capacity AS allsum
FROM(
select 
fma0.bldgcode, 
fma0.floorcode, 
sum(fma0.occ) as Occupancy, 
sum(CASE WHEN FMA0.SPACETYPE like 'A-OFF-%' OR 
    FMA0.SPACETYPE like 'A-WKS-%' THEN FMA0.CAPACITY 
    ELSE 0 END) as Capacity
from fma0 
where fma0.bldgcode = 'tst01' 
group by fma0.bldgcode, fma0.floorcode 

)tmp
order by bldgcode, floorcode

Answer 2

另一种选择是按如下方式使用CTE（注意到目前为止的其他答案都给出了SUM（SUM（占用）+ SUM（容量））：

WITH CTE_SUMS ([bldgcode], [floorcode], [Occupancy], [Capacity])
AS  (
    SELECT 
        fma0.bldgcode AS [bldgcode], 
        fma0.floorcode AS [floorcode], 
        sum(fma0.occ) AS [Occupancy], 
        sum(CASE WHEN FMA0.SPACETYPE like 'A-OFF-%' OR 
            FMA0.SPACETYPE like 'A-WKS-%' THEN FMA0.CAPACITY 
            ELSE 0 END) AS [Capacity]
    FROM fma0 
    WHERE fma0.bldgcode = 'tst01' 
    GROUP BY fma0.bldgcode, fma0.floorcode
    )
SELECT [bldgcode], [floorcode], [Occupancy], [Capacity], ([Occupancy] / [Capacity]) AS [Sum]
FROM CTE_SUMS

这基本上会给你SUM（占用）/ SUM（容量）以及已经考虑的分组。

Answer 3

SELECT 
bldgcode,
floorcode,
Occupancy,
Capacity ,
Occupancy+Capacity AS allsum
FROM(
select 
fma0.bldgcode, 
fma0.floorcode, 
sum(fma0.occ) as Occupancy, 
sum(CASE WHEN FMA0.SPACETYPE like 'A-OFF-%' OR 
FMA0.SPACETYPE like 'A-WKS-%' THEN FMA0.CAPACITY 
ELSE 0 END) as Capacity
from fma0 
where fma0.bldgcode = 'tst01' 
group by fma0.bldgcode, fma0.floorcode 
)tmp
order by bldgcode, floorcode

SQL Server 2008 - 总和

3 个答案: