Question

我有一个使用uin

的SQL查询

    SELECT Sum(scores_ofexpert.score) FROM scores_ofexpert
    WHERE scores_ofexpert.user_id = '30' AND scores_ofexpert.score > '0'
    UNION
    SELECT Sum(scores_ofexpert.score) FROM scores_ofexpert
    WHERE scores_ofexpert.user_id = '30' AND scores_ofexpert.score < '0'
    UNION
    SELECT Sum(scores_ofexpert.score) FROM scores_ofexpert
    WHERE scores_ofexpert.user_id = '30'

这个负分数的提取和，正斜率的总和和用户的所有分数的总和; 像这样

 -------------
 |-10        |
 -------------
 |30         |
 -------------
 |20         |
 -------------

但我希望结果为

 -------------------------------------
 |n_sum      |p_sum      |sum        |
 -------------------------------------    
 |-10        |30         |20         |
 -------------------------------------

怎么做？

Answer 1

您可以使用CASE

 SELECT
 SUM(CASE WHEN s.score < 0 THEN s.score ELSE 0 END) n_sum,
 SUM(CASE WHEN s.score > 0 THEN s.score ELSE 0 END) p_sum,
 SUM(s.score) `sum`
 FROM scores_ofexpert s
   WHERE s.user_id = '30'

Answer 2

这是另一个答案

SELECT
( SELECT Sum(scores_ofexpert.score)  
    FROM scores_ofexpert  
    WHERE   
    scores_ofexpert.user_id = '30' AND 
    scores_ofexpert.score > '0'
) p_sum,
(       SELECT
        Sum(scores_ofexpert.score)
        FROM
        scores_ofexpert
        WHERE
        scores_ofexpert.user_id = '30' AND
        scores_ofexpert.score < '0'
) n_sum,
(       SELECT
        Sum(scores_ofexpert.score)
        FROM
        scores_ofexpert
        WHERE
        scores_ofexpert.user_id = '30'
) sum_all

Answer 3

SELECT
 sum(if(s.score > '0',s.score, 0)) as  p_sum,
 sum(if(s.score < '0',s.score, 0)) as n_sum,
 SUM(s.score) as t_sum
 FROM scores_ofexpert s
   WHERE s.user_id = '30'

在mysql中加入3个字段

3 个答案: