Scala中公共静态最终字段的等效项

Question

我正在学习Scala，我无法弄清楚如何在Scala中最好地表达这个简单的Java类：

public class Color {
  public static final Color BLACK = new Color(0, 0, 0);
  public static final Color WHITE = new Color(255, 255, 255);     
  public static final Color GREEN = new Color(0, 0, 255);

  private final int red;
  private final int blue;
  private final int green;

  public Color(int red, int blue, int green) {
    this.red = red;
    this.blue = blue;
    this.green = green;
  }

  // getters, et cetera
}

我所拥有的最好成绩如下：

class Color(val red: Int, val blue: Int, val green: Int)
object BLACK extends Color(0, 0, 0)
object WHITE extends Color(255, 255, 255)
object GREEN extends Color(0, 0, 255)  

但是我失去了将BLACK，WHITE和GREEN与Color命名空间联系起来的优势。

Answer 1

case class Color(red: Int, blue: Int, green: Int)

object Color {
  val BLACK = Color(0, 0, 0)
  val WHITE = Color(255, 255, 255)
  val GREEN = Color(0, 0, 255)
}

Answer 2

您可以将特定颜色放入伴侣对象中：

class Color(val red: Int, val blue: Int, val green: Int)
object Color {
  object BLACK extends Color(0, 0, 0)
  object WHITE extends Color(255, 255, 255)
  object GREEN extends Color(0, 0, 255)
}

---

修改：

或者，您可以在随播对象中包含val：

class Color(val red: Int, val blue: Int, val green: Int)
object Color {
  val BLACK = new Color(0, 0, 0)
  val WHITE = new Color(255, 255, 255)
  val GREEN = new Color(0, 0, 255)
}

你可以让他们懒得延迟实例化直到使用它们：

class Color(val red: Int, val blue: Int, val green: Int)
object Color {
  lazy val BLACK = new Color(0, 0, 0)
  lazy val WHITE = new Color(255, 255, 255)
  lazy val GREEN = new Color(0, 0, 255)
}

回到原始解决方案，你可以阻止类的扩展（通过使Color类密封来模拟“final”：

sealed class Color(val red: Int, val blue: Int, val green: Int)
object Color {
  object BLACK extends Color(0, 0, 0)
  object WHITE extends Color(255, 255, 255)
  object GREEN extends Color(0, 0, 255)
}

Answer 3

sealed允许对象扩展具有相同的物理文件。不在不同的文件中。密封比最终包装范围更接近。