Question

我试图将avg作为程序的一部分运行。程序通常是自动执行的，所以我看不到python的标准输出。

当我通过直接调用程序运行程序时，它运行正常，但是当我通过自动化运行它时，它会失败。

它会在syslog中说 - ＆gt; ＆＃34;开始扫描：xxx＆＃34;，但它从未说过＆＃34;意外错误＆＃34;或＆＃34;扫描结果＆＃34;。这意味着，它失败了，但没有使用catch语句，或报告＆＃34; out＆＃34;变量

违规功能：

# Scan File for viruses
# fpath -> fullpath, tname -> filename, tpath -> path to file
def scan(fpath, tname, tpath):
    syslog("Starting scan of: " + tname)
    command = ["avgscan",
          "--report=" + tpath + "scan_result-" + tname +".txt",
          fpath]
    try:
        out = subprocess.call(command)
        syslog("Scan Results: " + str(out))
    except:
        syslog("Unexpected error: " + sys.exc_info()[0])
    finally:
        syslog("Finished scan()")

到目前为止，这两个想法都围绕着调试代码本身，在此之前，扫描只是一个简单的subprocess.call（命令），带有简单的syslog输出。使用with语句，try catch被添加以帮助调试。

Answer 1

我怀疑错误实际上来自打开调试文件; with语句不会阻止异常被引发。事实上，他们通常会提出自己的例外情况。

请注意try / except块范围的更改。

# Scan File for viruses
# fpath -> fullpath, tname -> filename, tpath -> path to file
def scan(fpath, tname, tpath):
    syslog("Starting scan of: " + tname)
    command = ["avgscan",
        "--report=" + tpath + "scan_result-" + tname +".txt",
        fpath]
    try:
        with open(tpath + tname + "-DEBUG.txt", "w") as output:
            out = subprocess.call(command, stdout = output, stderr = output)
            syslog("Scan Results: " + str(out))
    except:
        syslog("Unexpected error: " + sys.exc_info()[0])
    finally:
        syslog("Finished scan()")

Answer 2

所以我解决了。解决了这个问题，因为我不再使用AVG Scan，而是使用libclamscan。

通过使用直接使用python的扫描程序，结果更快，错误全部消失。如果有人通过搜索遇到这个，这里是我现在使用的代码：

import os.path
import pyclamav.scanfile

def r_scan(fpath):
    viruslist = []
    if os.path.isfile(fpath):
        viruslist = f_scan(fpath, viruslist)
    for root, subFolders, files in os.walk(fpath):
        for filename in files:
            viruslist = f_scan(
                             os.path.join(root, filename), viruslist)
    writeReport(fpath, viruslist)

def f_scan(filename, viruslist):
    result = pyclamav.scanfile(filename)
    if result[0] > 0:
        viruslist.append([result[1], filename])
    return viruslist

def writeReport(fpath, viruslist):
    header = "Scan Results: \n"
    body = ""
    for virusname, filename in viruslist:
        body = body + "\nVirus Found: " + virusname + " : " + filename

    with open(fpath + "-SCAN_RESULTS.txt", 'w') as f:
        f.write(header+body)

调试python不会尊重catch语句

2 个答案: