Question

我有问题在下面的代码中添加JS变量“vpath”：

var vpath = myarr[0];
jwplayer("player").setup({
   flashplayer: "player.swf",
    config:"config.xml",
    autostart: false,
    allowscriptaccess: "always",
    height: 500,
    width: 625,
    plugins: {
   'http//www.test.com/'+ vpath +'/proxy.swf': {link:"http://www.test.com/link.php"},
   'http//www.test.com/image.swf': {link:"http://www.test.com/image.jpg"}
    }
    });

存在SyntaxError：missing：属性id之后。现在有人怎么做？谢谢。

Answer 1

您不能在object literals内的属性名称中使用变量（精确的语法和语义在§11.1.5中指定）。解决方案是首先使用任何静态属性定义对象，然后向对象添加任何动态属性。

在您的情况下，我建议您单独创建plugins对象，如下所示：

var vpath = myarr[0];
var plugins = {};
plugins['http//www.test.com/image.swf'] = {link:"http://www.test.com/image.jpg"}
plugins['http//www.test.com/'+ vpath +'/proxy.swf'] = {link:"http://www.test.com/link.php"};
jwplayer("player").setup({
   flashplayer: "player.swf",
   config:"config.xml",
   autostart: false,
   allowscriptaccess: "always",
   height: 500,
   width: 625,
   plugins: plugins
});

另一种在某些情况下可能有用的替代方法是使用IIFE：

var vpath = myarr[0];
jwplayer("player").setup({
   flashplayer: "player.swf",
   config:"config.xml",
   autostart: false,
   allowscriptaccess: "always",
   height: 500,
   width: 625,
   plugins: (function() {
           var obj = {};
           obj['http//www.test.com/image.swf'] = {link:"http://www.test.com/image.jpg"}
           obj['http//www.test.com/'+ vpath +'/proxy.swf'] = {link:"http://www.test.com/link.php"};
       })()
});

Javascript属性中的var

1 个答案: