Question

除了我想从$_POST["user"]插入值的一个字段外，有没有办法插入select语句中的大部分值？我需要两个查询才能这样做吗？

$sql = "INSERT INTO `TAB1` (name,category, brand, image_url,big_img)
        SELECT a.name,b.category, b.brand, a.image_url,a.big_img
        FROM `mTaB2` a INNER JOIN `mTab3` b
        ON a.tid = b.id 
        WHERE a.id = ?           
       ";
$users = $dbh->prepare($sql);
$users->bindValue(1, $_POST["id"]);
$result = $users->execute();          

...............

$sql = "INSERT INTO `TAB1` (user)
        VALUES(?)
       ";

$users = $dbh->prepare($sql);
$users->bindValue(1, $_POST["user"]);
$result = $users->execute();

Answer 1

我认为这样的事情会奏效：

$sql = "INSERT INTO `TAB1`(user, name, category, brand, image_url, big_img)
        SELECT ?, a.name, b.category, b.brand, a.image_url, a.big_img
        FROM `mTaB2` a INNER JOIN `mTab3` b
        ON a.tid = b.id 
        WHERE a.id = ?           
       ";
$users = $dbh->prepare($sql);
$users->bindValue(1, $_POST["user"]);
$users->bindValue(2, $_POST["id"]);

Answer 2

不需要两个查询：

$sql = "INSERT INTO `TAB1` (user,name,category, brand, image_url,big_img)
        SELECT ?,a.name,b.category, b.brand, a.image_url,a.big_img
        FROM `mTaB2` a INNER JOIN `mTab3` b
        ON a.tid = b.id 
        WHERE a.id = ?           
       ";
$users = $dbh->prepare($sql);
$users->bindValue(1, $_POST["user"]);
$users->bindValue(2, $_POST["id"]);
$result = $users->execute();

从select语句INSERT INTO除了mysql中的一个字段

2 个答案: