我是C语言编程的新手,我试图找出结构的正确用法,作为一个例子:
int main (int argc, char *argv[])
{
char player_one = "bob";
char player_two = "steve";
enum colour
{
P_RED, P_WHITE
};
struct player
{
char name[MAX_NAME_LEN+1];
enum colour col;
};
int rndNumber;
srand (time(NULL));
rndNumber = rand() % 2;
struct player p1 = {player_one, rndNumber};
struct player p2 = {player_two, rndNumber};
printf("%s\n", p1.name);
printf("%d\n", p1.col);
printf("%s\n", p2.name);
printf("%d\n", p2.col);
return EXIT_SUCCESS;
}
当我尝试编译此代码时,我遇到了几个错误。
warning: initialization makes integer from pointer without a cast [enabled by default]
char player_one = "bob";
warning: missing braces around initializer [-Wmissing-braces]
struct player p1 = {player_one, rndNumber};
warning: (near initialization for ‘p1.name’) [-Wmissing-braces]
warning: initializer element is not computable at load time [enabled by default]
warning: ISO C90 forbids mixed declarations and code [-Wpedantic]
struct player p1 = {player_one, rndNumber};
这样做是为了使p1.name和p2.name不打印,p1.col和p2.col总是打印0,即使rndNumber成功打印随机数。那么我在这里做错了什么? o.O
答案 0 :(得分:3)
在C中,字符串不是字符,而是字符数组。所以声明他们是这样的:
char *player_one = "bob";
或
char player_one[] = "bob";
其次,在结构中,您可以将字符串声明为:
char name[MAX_NAME_LEN+1];
或
char *name;
不同之处在于,在第一种情况下,分配了MAX_NAME_LEN+1
个字符,在第二种情况下,name
只是一个指针。所以在第一种情况下,你需要复制蜇伤:
strcpy(p1.name, player_one);
在第二种情况下,任务将执行:
p1.name = player_one;
或正如你所做的那样:
p1 = {player_one, rndNumber};
答案 1 :(得分:0)
首先,在main()函数之外定义新类型:
#define MAX_NAME_LEN 100
typedef enum
{
RED, WHITE
} Color;
typedef struct
{
char *name;
Color color;
} Player;
然后,在main()函数中,您可以使用这样的新类型:
char *player_one = "bob";
char *player_two = "steve";
Color redColor = RED;
Color whiteColor2 = WHITE;
Player p1 = { player_one, redColor };
Player p2 = { player_two, whiteColor2 };
printf("%s\n", p1.name);
printf("%d\n", p1.color);
printf("%s\n", p2.name);
printf("%d\n", p2.color);
p1.name = "john";
p2.color = RED;
printf("%s\n", p1.name);
printf("%d\n", p1.color);
printf("%s\n", p2.name);
printf("%d\n", p2.color);