Question

我希望用户能够更改按钮的标题，这是我打算做的硬编码示例：

   [myButton setTitle:@"B" forState:UIControlStateNormal];

但是，我宁愿用UIPicker提示用户，并允许用户从多个选项中进行选择以更改标题。

- (IBAction)handleLongPress:(UILongPressGestureRecognizer *)sender {
    UILongPressGestureRecognizer *lpgr = [[UILongPressGestureRecognizer alloc]
                                          initWithTarget:self action:@selector(handleLongPress:)];
    lpgr.minimumPressDuration = 1.0;

   if ([sender.view isKindOfClass:[UIButton class]]) {
      NSLog(@"user has clicked the button%@", sender.view);
      UIButton *myButton = (UIButton *)sender.view;
       UIPickerView *picker = [[UIPickerView alloc] init];
       myButton.titleLabel = picker;

   }

}

此时我看到错误*assignment to readonly property是否可以将UIPickerView与UIButton的setTitle属性结合使用？如果是这样，这是如何实现的？

Answer 1

错误很明显：

titleLabel是UIButton类的UILabel属性，它是只读的（不能将其设置为其他值）。您需要使用其标签的文本属性：

myButton.titleLabel.text = @"some text";

而不是：

myButton.titleLabel = picker;

或

myButton.titleLabel.text = picker;

因为picker不是NSString对象。

让我在一分钟内解释如何实现这个......

在View Controller类中，创建一个属性（我建议在私有界面中执行），并实现UIPickerViewDataSource，UIPickerViewDelegate协议：

@interface PPMyViewController () <UIPickerViewDataSource, UIPickerViewDelegate>

@property (nonatomic, strong) UIPickerView *pickerView;

@end

现在，对pickerView属性使用lazy instantiation：

- (UIPickerView *)pickerView
{
    if (!_pickerView)
    {
        _pickerView = [[UIPickerView alloc] initWithFrame:CGRectMake(0, 0, 320, 100)];
        _pickerView.dataSource = self;
        _pickerView.delegate = self;
    }

    return _pickerView;
}

Make sure you add to the main view, you can do it in the viewDidLoad method:

- (void)viewDidLoad
{
   [super viewDidLoad];

   [self.view addSubview:self.pickerView];
}


And implement most of the 2 protocols methods:

#pragma mark - UIPickerViewDataSource Methods

// returns the number of 'columns' to display.
- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView
{
    return 1;
}

// returns the # of rows in each component..
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component
{
    return 10;
}

#pragma mark - UIPickerViewDelegate Methods

- (CGFloat)pickerView:(UIPickerView *)pickerView widthForComponent:(NSInteger)component;
{
    return 200;
}

- (CGFloat)pickerView:(UIPickerView *)pickerView rowHeightForComponent:(NSInteger)component
{
    return 50;
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
    return [NSString stringWithFormat:@"row %d", row];
}

- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
    NSLog(@"Row %d selected", row);
//    myButton.titleLabel.text = @"text you need depending on row selection";
}

请注意，我的代码会始终在底部显示UIPickerView。您可以根据需要隐藏/取消隐藏它。或者更好的是，使用动画将其定位在屏幕外而不是隐藏。

Answer 2

你不能像你想的那样做。您需要做的是听取用户点击按钮，然后向用户显示一个选择器。

有一些开源控件可以简化此操作，例如ActionSheetPicker。

使用UIPickerView编辑UIButton的文本

2 个答案: