Question

class Shape:

    def __init__(self, x, y, name, age):
        self.x = x
        self.y = y
        self.name = name
        self.age = age
        description = "This shape has not been described yet"
        author = "Nobody has claimed to make this shape yet"

    def area(self):
        return self.x * self.y

    def perimeter(self):
        return 2 * self.x + 2 * self.y

    def describe(self,text):
        self.description = text

    def authorName(self,text):
        self.author = text

    def scaleSize(self,scale):
        self.x = self.x * scale
        self.y = self.y * scale

如何在authorName，describe和scaleSize中打印属性，因为到目前为止我只能实现这个结果。

objectname = Shape(8,10, 'Peter Adom', '55')

print(objectname.name)
print(objectname.area())
print(objectname.perimeter())

Answer 1

你可以看到函数area和perimeter有一个return子句，因为它们应该计算一些不能直接访问的东西（你有{{1} }和x但您没有存储区域或周长的属性。这在编程中很常见，因为如果您有y属性，这可能与area计算的值不同，从而带来不一致。

方法self.x * self.y，describe和authorName用于更改对象的某些属性。它们不返回任何内容，它们在对象中设置值。

为了检索对象的属性，您应该直接访问它们。但这对scaleSize和description不起作用，因为您没有在对象命名空间中设置属性。事实上，方法author中的行应该是：

__init__

之后你就能做到：

self.description = "This shape has not been described yet"
self.author = "Nobody has claimed to make this shape yet"

您应该考虑以明确其目的的方式命名您的二传手，例如objectname = Shape(8,10, 'Peter Adom', '55') print(objectname.author) # Nobody has claimed to make this shape yet objectname.authorName("Me") print(objectname.author) # Me print(objectname.description) # This shape has not been described yet objectname.describe("Wonderful shape") print(objectname.description) # Wonderful shape和setAuthor。

Python类和方法

1 个答案: