Question

在mysql中我有3个表叫做

ps_product_lang

ps_order_detail

and ps_image

这里是表格样本数据

=== ps_product_lang ===


CREATE TABLE IF NOT EXISTS `ps_product_lang` (
  `id_product` int(10) unsigned NOT NULL,
  `id_shop` int(11) unsigned NOT NULL DEFAULT '1',
  `id_lang` int(10) unsigned NOT NULL,
  `description` text,
  `description_short` text,
  `name` varchar(128) NOT NULL,
  PRIMARY KEY (`id_product`,`id_shop`,`id_lang`),
  KEY `id_lang` (`id_lang`),
  KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

--
-- Dumping data for table `ps_product_lang`
--

INSERT INTO `ps_product_lang` (`id_product`, `id_shop`, `id_lang`, `description`, `description_short`,  `name`) VALUES
(1, 1, 1, '<p>this is dummy</p>', '<p>dummy</p>', 'dummy product')
);


===== ps_order_detail===
    CREATE TABLE IF NOT EXISTS `ps_order_detail` (
      `id_order_detail` int(10) unsigned NOT NULL AUTO_INCREMENT,
      `id_order` int(10) unsigned NOT NULL,
      `product_id` int(10) unsigned NOT NULL,
      PRIMARY KEY (`id_order_detail`),
      KEY `product_id` (`product_id`)
    ) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=16 ;

    --
    -- Dumping data for table `ps_order_detail`
    --

    INSERT INTO `ps_order_detail` (`id_order_detail`, `id_order`,  `product_id`) VALUES
    (1, 1, 2);

========= ps_image =========
CREATE TABLE IF NOT EXISTS `ps_image` (
  `id_image` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `id_product` int(10) unsigned NOT NULL,
  `position` smallint(2) unsigned NOT NULL DEFAULT '0',
  `cover` tinyint(1) unsigned NOT NULL DEFAULT '0',
  PRIMARY KEY (`id_image`),
  UNIQUE KEY `idx_product_image` (`id_image`,`id_product`,`cover`),
  KEY `image_product` (`id_product`),
  KEY `id_product_cover` (`id_product`,`cover`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=24 ;

--
-- Dumping data for table `ps_image`
--

INSERT INTO `ps_image` (`id_image`, `id_product`, `position`, `cover`) VALUES
(1, 1, 1, 1),
(2, 1, 2, 0),
(3, 1, 3, 0),
(4, 1, 4, 0),
(5, 2, 1, 0),
(6, 2, 2, 0),
(7, 2, 3, 1),
(8, 3, 1, 1),
(9, 3, 2, 0),
(10, 4, 1, 1),
(11, 4, 2, 0),
(12, 5, 1, 1),
(13, 5, 2, 0),
(14, 5, 3, 0),
(15, 5, 4, 0),
(16, 6, 1, 1),
(17, 6, 2, 0),
(18, 6, 3, 0),
(19, 6, 4, 0),
(20, 7, 1, 1),
(21, 7, 2, 0),
(22, 7, 3, 0),
(23, 7, 4, 0);

所以在这里我希望得到所有的领域，如

id_order_detail id_product name id_image(from ps_image table where cover = 1)

获取id_order_detail id_product名称我正在使用这个mysql内连接

SELECT DISTINCT (a.id_order_detail),(b.id_product),(b.name)
        FROM ps_order_detail a join 
        ps_product_lang b on a.product_id=b.id_product GROUP BY(name)

这个给了我id_order_detail id_product name

现在我想获得id_image from the ps_image table where the cover value is 1 for the product_id

有人能告诉我怎么做这个吗？任何帮助和建议都会非常明显。感谢

Answer 1

你能不能只加入product_id上的第三个表格吗？像这样

SELECT a.id_order_detail, b.id_product, b.name, c.id_image
FROM ps_order_detail a 
join ps_product_lang b on a.product_id=b.id_product 
join ps_image c on c.id_product = a.product_id
where c.cover = 1

使用MySQL连接从表中获取值

1 个答案: