Question

我正在研究我的应用程序上的intuit集成。现在，我面临一个关于调用intuit的重新连接api的问题。我正在关注此引用：http://oauth.net/core/1.0a/

我正在尝试使用此代码::

Base64Encoder baseEncoder = Base64Encoder.getInstance();
            Intuit intuit = IntuitLocalServiceUtil.getIntuit();// this is object, which stores the oauth Token and Oauth token secret. 
            CloseableHttpClient httpclient = HttpClients.createDefault();
            HttpGet httpGet = new HttpGet("https://appcenter.intuit.com/api/v1/connection/reconnect");
            StringBuilder headerReq = new StringBuilder();
            headerReq.append("OAuth ");
            headerReq.append("oauth_token=\"").append(intuit.getOauthToken()).append("\"");
            headerReq.append(", oauth_consumer_key=\"").append(CommonConstants.INTUIT_QB_OAUTH_CONSUMER_KEY).append("\"");
            headerReq.append(", oauth_signature_method=\"base64\"");
            headerReq.append(", oauth_signature=\"")
                    .append(baseEncoder.encode(PropsUtil.get(CommonConstants.INTUIT_QB_OAUTH_CONSUMER_SECRET).getBytes()))
                    .append(baseEncoder.encode("&".getBytes()))
                    .append(baseEncoder.encode(symmetricEncrypter.decryptData(intuit.getOauthTokenSecret()).getBytes())).append("\"");

            headerReq.append(", oauth_version=\"1.0\"");
            httpGet.addHeader("Authorization", headerReq.toString());
            System.out.println("Header Rwquesssssssssssst::::::" + headerReq.toString());
            CloseableHttpResponse response = httpclient.execute(httpGet);
            try {
                System.out.println("Responsee::"+ response.getStatusLine());
}

每次我收到此回复：

<?xml version="1.0" encoding="utf-8"?>
<PlatformResponse xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://platform.intuit.com/api/v1">
  <ErrorMessage>This API requires Authorization.</ErrorMessage>
  <ErrorCode>22</ErrorCode>
  <ServerTime>2014-08-16T18:15:45.6417185Z</ServerTime>
</PlatformResponse>
<?xml version="1.0" encoding="utf-8"?>
<PlatformResponse xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://platform.intuit.com/api/v1">
  <ErrorMessage>Authentication required</ErrorMessage>
  <ErrorCode>22</ErrorCode>
  <ServerTime>2014-08-16T18:15:47.3382208Z</ServerTime>
</PlatformResponse>

我使用邮递员测试了相同的东西，但我在响应时遇到了相同类型的错误。我确信，我的密钥是有效的，他们现在正在工作。

（PS：我知道，那些密钥只能在150到180天内重新生成，但我期待intuit api的窗口绑定异常，但我没有得到那些类型的有效错误，我只是收到身份验证错误。）

谢谢。

Answer 1

使用SignPost解决了这个问题，因为因纽特人的JAVA devkit有一个bug。

import java.io.InputStream;
import java.io.StringWriter;
import java.net.URI;
import java.net.URISyntaxException;

import oauth.signpost.OAuthConsumer;
import oauth.signpost.commonshttp.CommonsHttpOAuthConsumer;
import oauth.signpost.exception.OAuthCommunicationException;
import oauth.signpost.exception.OAuthExpectationFailedException;
import oauth.signpost.exception.OAuthMessageSignerException;
import oauth.signpost.signature.AuthorizationHeaderSigningStrategy;

import org.apache.commons.io.IOUtils;
import org.apache.http.HttpHost;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpRequestBase;
import org.apache.http.impl.client.DefaultHttpClient;

import com.intuit.ipp.data.Account;
import com.intuit.ipp.exception.FMSException;
import com.intuit.ipp.net.MethodType;
import com.intuit.ipp.services.DataService;

public class POCWithoutDevkitTest {

    private DataService service;
    private OAuthConsumer oAuthConsumer;
    private static String realmID = null;

    public POCWithoutDevkitTest() {
        realmID = "122294642099";
        String consumerKey = "AAAAA";
        String consumerSecret = "BBBBB";
        String accessToken = "CCCCC";
        String accessTokenSecret = "DDDDD";

        setupContext(consumerKey, consumerSecret, accessToken, accessTokenSecret);
    }

    public void setupContext(String consumerKey, String consumerSecret, String accessToken, String accessTokenSecret) {
            this.oAuthConsumer = new CommonsHttpOAuthConsumer(consumerKey, consumerSecret);
            oAuthConsumer.setTokenWithSecret(accessToken, accessTokenSecret);
            oAuthConsumer.setSigningStrategy(new AuthorizationHeaderSigningStrategy());
    }

    public void authorize(HttpRequestBase httpRequest) throws FMSException {
        try {
            oAuthConsumer.sign(httpRequest);
        } catch (OAuthMessageSignerException e) {
            throw new FMSException(e);
        } catch (OAuthExpectationFailedException e) {
            throw new FMSException(e);
        } catch (OAuthCommunicationException e) {
            throw new FMSException(e);
        }
    }

    public void executeGetRequest(String customURIString){
        DefaultHttpClient client = new DefaultHttpClient();
        client.getParams().setParameter("http.protocol.content-charset", "UTF-8");

        HttpRequestBase httpRequest = null;
        URI uri = null;

        try {
            uri = new URI(customURIString);
        } catch (URISyntaxException e) {
            e.printStackTrace();
        }

        String methodtype = "GET";

        if (methodtype.equals(MethodType.GET.toString())) {
            httpRequest = new HttpGet(uri);
        }

        httpRequest.addHeader("content-type", "application/xml");
        httpRequest.addHeader("Accept","application/xml");

        try {
            authorize(httpRequest);
        } catch (FMSException e) {
            e.printStackTrace();
        }


        HttpResponse httpResponse = null;
        try {
            HttpHost target = new HttpHost(uri.getHost(), -1, uri.getScheme());
            httpResponse = client.execute(target, httpRequest);
            System.out.println("Connection status : " + httpResponse.getStatusLine());

            InputStream inputStraem = httpResponse.getEntity().getContent();

            StringWriter writer = new StringWriter();
            IOUtils.copy(inputStraem, writer, "UTF-8");
            String output = writer.toString();

            System.out.println(output);
        }catch(Exception e){
            e.printStackTrace();
        }
    }

    public static void main(String args[]) {
        POCWithoutDevkitTest withoutDevkitClient = new POCWithoutDevkitTest();
        withoutDevkitClient.executeGetRequest("https://appcenter.intuit.com/api/v1/connection/reconnect");
    }

}

依赖是：

<dependency>
        <groupId>org.apache.httpcomponents</groupId>
        <artifactId>httpcore</artifactId>
        <version>4.3.1</version>
    </dependency>
    <dependency>
        <groupId>oauth.signpost</groupId>
        <artifactId>signpost-core</artifactId>
        <version>1.2.1.1</version>
    </dependency>
    <dependency>
        <groupId>oauth.signpost</groupId>
        <artifactId>signpost-commonshttp4</artifactId>
        <version>1.2</version>
    </dependency>
    <dependency>
        <groupId>org.apache.commons</groupId>
        <artifactId>commons-io</artifactId>
        <version>1.3.2</version>
    </dependency>
    <dependency>
        <groupId>org.apache.httpcomponents</groupId>
        <artifactId>httpmime</artifactId>
        <version>4.3.1</version>
    </dependency>

谢谢。

Answer 2

您使用的是哪种SDK？对于PHP，您可以参考此示例 - https://gist.github.com/IntuitDeveloperRelations/8292870

对于dotnet-使用dev定义的调用 - 开发人员定义的调用示例 - https://gist.github.com/IntuitDeveloperRelations/0913b4c224de758fde0a

同样，您可以调用平台服务

Refer- https://developer.intuit.com/docs/0025_quickbooksapi/0053_auth_auth/oauth_management_api#Reconnect

请查看以下有关创建短期OAuth令牌以测试重新连接的说明。

导航至IPP Playground-转至管理我的应用 - ＆gt;点击您的应用

在下面的链接中填写消费者密钥和消费者密钥。

产品：https://appcenter.intuit.com/Playground/OAuth/IA/?ck=＆lt;＆gt;＆amp; cs =＆lt;＆gt;

或者，您可以在舞台或prod上导航到应用程序的“管理”页面，然后单击“测试连接到应用程序（OAuth）”。

在“访问令牌持续时间”字段中输入您希望发布的OAuth令牌的持续时间（例如，成功重新连接时为3600）。附加屏幕截图。
单击“连接到QuickBooks”按钮，浏览OAuth流程以授权与领域的连接。
在生成的“连接后交互”标题下，单击“重新连接API测试”。
将在您的OAuth令牌显示位置启动新页面。将这些值复制到您的应用程序以测试重新连接。

如何调用intuit reconnnect api（OAuth1.0）？

2 个答案: