Question

我想在1-20的imacros中生成随机数，但是没有REPEAT，我有一个代码，任何人都可以修改它吗？

我有数据源文件data.csv，它有1x1行/列，有20行数据。

SET !DATASOURCE data.csv
SET !VAR2 EVAL("var randomNumber=Math.floor(Math.random()*20 + 1); randomNumber;")
SET !DATASOURCE_LINE {{!VAR2}}

EVENT TYPE=CLICK SELECTOR="HTML>BODY>DIV>DIV:nth-of-type(2)>DIV>DIV>DIV>DIV>DIV:nth-of-type(3)>DIV>FORM>TEXTAREA" BUTTON=0
EVENTS TYPE=KEYPRESS SELECTOR="HTML>BODY>DIV>DIV:nth-of-type(2)>DIV>DIV>DIV>DIV>DIV:nth-of-type(3)>DIV>FORM>TEXTAREA" CHARS="{{!COL1}}"
TAG POS=1 TYPE=INPUT:SUBMIT FORM=NAME:NoFormName ATTR=*

Answer 1

在Java中你可以做到。

List<Integer> ints = new ArrayList<Integer>();
for (int i = 1; i <= 20; i++) ints.add(i);
Collections.shuffle(ints);

Answer 2

在这里放一个while循环，你可以得到一个有效的代码。摘自：

Generating random whole numbers in JavaScript in a specific range?

var array_of_numbers=null;
var random_number = null;

random_number=getRandomArbitrary(1,20);

if(array_of_numbers.indexOf(random_number)>0)
{
random_number=getRandomArbitrary(1,20);
}
else
{
array_of_numbers.push(random_number);
}


/**
 * Returns a random number between min (inclusive) and max (exclusive)
 */
function getRandomArbitrary(min, max) {
    return Math.random() * (max - min) + min;
}

/**
 * Returns a random integer between min (inclusive) and max (inclusive)
 * Using Math.round() will give you a non-uniform distribution!
 */
function getRandomInt(min, max) {
    return Math.floor(Math.random() * (max - min + 1)) + min;
}

Answer 3

在java中，这将生成1到20之间的随机数

ArrayList<Integer> arrOfRandomNumber = new ArrayList<Integer>();
Random randomGenerator = new Random();
while (arrOfRandomNumber.size() < 20) {
    int random = randomGenerator .nextInt(20);
    if (!arrOfRandomNumber.contains(random+1)) {   
       arrOfRandomNumber.add(random+1);
 }
}

我想在1-20的imacros中生成随机数，但不要重复

3 个答案: