Question

我有两个以弧度为单位的值c[1]和c[3]。我需要将弧度转换为度数，并且我不知道如何对这些数字做些什么来获得它们的度数。我一直在寻找互联网，我无法找到任何我能理解的东西。我已经尝试设计自己的方式来做到这一点，但我确定我甚至没有接近。我尝试过以下方法：

    z = (((c[1] * 180) + 180) + ((c[3] * 180) + 180))
    z = (((c[1] * math.pi) / 180) + ((c[3] * math.pi) / 180) / 2)
    z = (c[1] * (90/math.pi) - (c[3] * (90/math.pi)))
    z = math.atan2(c[3], c[1])
    z = (math.degrees(c[1]) + math.degrees(c[3])) * 2
    z = c[1]
    z = (math.asin(c[3]) / math.acos(c[1]))

如何从2弧度获得度数值？

Answer 1

弧度转换的程度用公式（n deg）*（pi / 180度）完成。

z = (c[1]*(math.pi/180.0) + (c[1]*(math.pi/180)

如果你需要经常做一些功能。

def DegtoRad(deg):
    return (deg)*(math.pi/180)

或作为lambda

DegtoRad = lambda x: x*(math.pi/180)

记住，如果你没有导入math / math.pi，这一切都不会起作用。最好用实际的文字变量来定义pi，直到你的精度需求。

Answer 2

这在网上找不是很难吗？ - 是吗？

http://www.mathwarehouse.com/trigonometry/radians/convert-degee-to-radians.php

该公式与@ user2913685的公式相反：num * 180 / pi （一个容易犯的错误）

这是python的一个例子：

pi = 3.14159265

rad_val = 7

deg_val = rad_val*180/pi

print(deg_val)

给出输出：

401.07045704986604

这使用pi作为3.14159265，并且不使用模块数学。显然你可以像在另一个答案中那样做，但是在改变公式之后。

Answer 3

在完成你的评论之后，我不认为你得到c [1]和c [3]的弧度两个角度。相反，你正在获得方向余弦。如果您以弧度为单位获取角度，则值的范围为-pi到pi。相反，该值从-1到1（即cos（-pi）到cos（pi））。

您可以先将值更改为以弧度表示的角度，然后更改为度数（如果这是您想要的）。正如一个警告，角度的余弦是对称的...... 所以：

In [12]: zip(angles, (cos(angles)))
Out[12]:
[(-3.1415926535897931, -1.0),
 (-2.8108986900540254, -0.94581724170063464),
 (-2.4802047265182576, -0.78914050939639346),
 (-2.1495107629824899, -0.5469481581224267),
 (-1.8188167994467224, -0.24548548714079912),
 (-1.4881228359109546, 0.082579345472332394),
 (-1.1574288723751871, 0.40169542465296937),
 (-0.82673490883941936, 0.67728157162574099),
 (-0.49604094530365161, 0.87947375120648907),
 (-0.16534698176788387, 0.98636130340272232),
 (0.16534698176788387, 0.98636130340272232),
 (0.49604094530365161, 0.87947375120648907),
 (0.82673490883941891, 0.67728157162574132),
 (1.1574288723751867, 0.40169542465296976),
 (1.4881228359109544, 0.082579345472332616),
 (1.8188167994467221, -0.2454854871407989),
 (2.1495107629824899, -0.5469481581224267),
 (2.4802047265182576, -0.78914050939639346),
 (2.8108986900540254, -0.94581724170063464),
 (3.1415926535897931, -1.0)]

但是，

In [11]: zip(angles, arccos(cos(angles)))
Out[11]:
[(-3.1415926535897931, 3.1415926535897931),
 (-2.8108986900540254, 2.8108986900540254),
 (-2.4802047265182576, 2.4802047265182576),
 (-2.1495107629824899, 2.1495107629824899),
 (-1.8188167994467224, 1.8188167994467224),
 (-1.4881228359109546, 1.4881228359109546),
 (-1.1574288723751871, 1.1574288723751871),
 (-0.82673490883941936, 0.82673490883941936),
 (-0.49604094530365161, 0.49604094530365156),
 (-0.16534698176788387, 0.16534698176788418),
 (0.16534698176788387, 0.16534698176788418),
 (0.49604094530365161, 0.49604094530365156),
 (0.82673490883941891, 0.82673490883941891),
 (1.1574288723751867, 1.1574288723751867),
 (1.4881228359109544, 1.4881228359109544),
 (1.8188167994467221, 1.8188167994467221),
 (2.1495107629824899, 2.1495107629824899),
 (2.4802047265182576, 2.4802047265182576),
 (2.8108986900540254, 2.8108986900540254),
 (3.1415926535897931, 3.1415926535897931)]

这意味着从你的方向角度来看你的角度，你需要这样做：

In [13]: def toAng(a): return sign(a)*arccos(a)

将为您提供正确的角度：

In [19]: zip(angles, toAng(cos(angles)))
Out[19]:
[(-3.1415926535897931, -3.1415926535897931),
 (-2.8108986900540254, -2.8108986900540254),
 (-2.4802047265182576, -2.4802047265182576),
 (-2.1495107629824899, -2.1495107629824899),
 (-1.8188167994467224, -1.8188167994467224),
 (-1.4881228359109546, 1.4881228359109546),
 (-1.1574288723751871, 1.1574288723751871),
 (-0.82673490883941936, 0.82673490883941936),
 (-0.49604094530365161, 0.49604094530365156),
 (-0.16534698176788387, 0.16534698176788418),
 (0.16534698176788387, 0.16534698176788418),
 (0.49604094530365161, 0.49604094530365156),
 (0.82673490883941891, 0.82673490883941891),
 (1.1574288723751867, 1.1574288723751867),
 (1.4881228359109544, 1.4881228359109544),
 (1.8188167994467221, -1.8188167994467221),
 (2.1495107629824899, -2.1495107629824899),
 (2.4802047265182576, -2.4802047265182576),
 (2.8108986900540254, -2.8108986900540254),
 (3.1415926535897931, -3.1415926535897931)]

最后，如果你需要将它转换为度数，你可以这样做：

在[20]中：def toAng（a）：返回180 *符号（a）* arccos（a）/ pi

In [21]: zip(angles, toAng(cos(angles)))
Out[21]:
[(-3.1415926535897931, -180.0),
 (-2.8108986900540254, -161.05263157894737),
 (-2.4802047265182576, -142.10526315789474),
 (-2.1495107629824899, -123.1578947368421),
 (-1.8188167994467224, -104.21052631578948),
 (-1.4881228359109546, 85.263157894736835),
 (-1.1574288723751871, 66.31578947368422),
 (-0.82673490883941936, 47.368421052631582),
 (-0.49604094530365161, 28.421052631578949),
 (-0.16534698176788387, 9.4736842105263346),
 (0.16534698176788387, 9.4736842105263346),
 (0.49604094530365161, 28.421052631578949),
 (0.82673490883941891, 47.368421052631554),
 (1.1574288723751867, 66.315789473684191),
 (1.4881228359109544, 85.263157894736835),
 (1.8188167994467221, -104.21052631578947),
 (2.1495107629824899, -123.1578947368421),
 (2.4802047265182576, -142.10526315789474),
 (2.8108986900540254, -161.05263157894737),
 (3.1415926535897931, -180.0)]

这为你提供了角度的正确角度......

注意我正在使用sign，pi等是numpy对象的环境。在您的程序中，您可能需要单独导入它们。

将X，Y旋转坐标从Radians转换为Degrees

3 个答案: