Question

我正在寻找一种有效的方式来追踪回头客。

到目前为止我选择的选项列表：

每个用户，每天/每周/每月保存（更新）登录次数
保存（更新）用户已登录的文本字段（错误选择？），每天/每周/每月
通过其他数据库资源（来自多个表的用户添加记录）推断返回用户

我认为最后一个选项效率最高，因为我不需要创建单独的日志记录表。

然而，记录表似乎更准确，周期性，对吧？

更新

准确性仍然具有优先权，所以我选择了第一个选项，以及PHP中的一些逻辑。

我选择存储每周登录次数（年度），例如：201433。

问题：关于PHP代码，有没有办法将两个查询结合起来，省去嵌套循环（效率）？

数据库表：

+----+--------+--------+-----------+
| id | userId | logins | year_week |
+----+--------+--------+-----------+
|  1 |      1 |      4 |    201432 |
|  2 |      1 |      3 |    201433 |
|  3 |      2 |      2 |    201433 |
+----+--------+--------+-----------+

查询：

SELECT
    userId,
    SUM(logins) as total
FROM
    User_Logins
GROUP BY
    userId
ORDER BY
    userId

-----------

// get first year_week

SELECT
    userId,
    year_week
FROM
    User_Logins
GROUP BY
    userId
ORDER BY
    userId

查询结果：

+--------+-------+
| userId | total |
+--------+-------+
|      1 |     7 |
|      2 |     2 |
+--------+-------+

+--------+-----------+
| userId | year_week |
+--------+-----------+
|      1 |    201432 |
|      2 |    201433 |
+--------+-----------+

PHP代码：

$returningUsers = 0;

$userLogins = $this->model->firstQuery();
$userLoginWeeks = $this->model->secondQuery();


$today = new DateTime();


function weeksPassed($today, $year, $week)
{
    $today->setISODate($today->format('Y'), $today->format('W'));

    // year and week from user first login
    $yearWeek = new DateTime();
    $yearWeek->setISODate($year, $week);

    $daysPassed  = $today->diff($yearWeek)->days;
    $weeksPassed = $daysPassed / 7;

    return $weeksPassed;
}


if ($userLogins && $userLoginWeeks)
{
    foreach ($userLoginWeeks as $userLoginWeek)
    {
        $userId    = $userLoginWeek->userId;
        $year_week = $userLoginWeek->year_week;

        $year = (int) substr($year_week, 0, 4);
        $week = (int) substr($year_week, 4);

        $weeksPassed = weeksPassed($today, $year, $week);


        $totalLogins = 0;


        // Look up user logins from other query
        foreach ($userLogins as $logins)
        {
            if ($logins->userId == $userId)
            {
                $totalLogins = $logins->total;
                break;
            }
        }


        $avgLogins = $totalLogins;


        //  Average calculated over weeks that have passed since first login
        if ($weeksPassed > 0)
        {
            $avgLogins = $totalLogins / $weeksPassed;
        }


        // if average >= 1 per week  =>  returning user
        if ($avgLogins >= 1)
        {
            $returningUsers++;
        }
    }
}


return $returningUsers;

跟踪回访用户的有效方式？

0 个答案: