Question

我是websockets技术的新手。我试图创建一个websockets php服务器并使用javascript客户端连接到服务器。我正在使用xampp 1.8.3。

我制作了这个简单的PHP服务器：

<?php 
    error_reporting(E_ALL);
    set_time_limit(0);

    $address = "127.0.0.1";
    $port = 1777;
    $maxConnections = 10;

    if(!($sock = socket_create(AF_INET, SOCK_STREAM, 0))){
        $errorCode = socket_last_error();
        $errorMsg = socket_strerror($errorCode);
        die("socket_create() failed -> {$errorCode}:{$errorMsg}\n");
    }
    echo "Server created.\n";

    if(!(socket_bind($sock, $address, $port))){
        $errorCode = socket_last_error();
        $errorMsg = socket_strerror($errorCode);
        die("socket_bind() failed -> {$errorCode}:{$errorMsg}\n");
    }
    echo "Server opened on {$address}:{$port}\n";

    if(!(socket_listen($sock, $maxConnections))){
        $errorCode = socket_last_error();
        $errorMsg = socket_strerror($errorCode);
        die("socket_listen() failed -> {$errorCode}:{$errorMsg}\n");
    }
    echo "Waiting for connections...\n";

    $client = socket_accept($sock);
    if(socket_getpeername($client, $address, $port)){
        echo "The client {$address}:{$port} is online.\n";
    }
    $msg = socket_read($client, 1024000);
    if(!(socket_write($client, $msg, strlen($msg)))){
        $errorCode = socket_last_error();
        $errorMsg = socket_strerror($errorCode);
        die("socket_write() failed -> {$errorCode}:{$errorMsg}\n");
    }
    echo "Message sent\n";

    socket_close($client);
    socket_close($sock);


?>

我使用以下表达式使用xampp shell运行此php文件：

php htdocs/server.php

我在shell上收到了这条消息：

php htdocs/server.php
Server created.
Server opened on 127.0.0.1:1777
Waiting for connections...

然后我在chrome上打开了我的client.html（我的支持websockets）。我的client.html代码是：

<html>
    <head>
        <meta charset="UTF-8" />
        <title>Websockets web-server connection</title>
    </head>
    <body>
        <p>Websockets connection. Status: <span id="status"></span></p>
        <script type="text/javascript">
            var webSockets = new WebSocket("ws://127.0.0.1:1777/");
            webSockets.onopen = function(){
                document.getElementById("status").innerHTML="connected";
                webSockets.send("ping");
            }
        </script>
    </body>
</html>

我在javascript控制台日志中收到此消息：

WebSocket connection to 'ws://127.0.0.1:1777/' failed:  client.html:9

我的shell有这样的消息：

php htdocs/server.php
Server created.
Server opened on 127.0.0.1:1777
Waiting for connections...
The client 127.0.0.1:64446 is online
Message sent

但是我没有在客户端收到任何消息，我甚至没有获得连接状态。

发生了什么事？我的错误在哪里？

谢谢。

Answer 1

WebSockets不是原始TCP套接字。它们需要相当复杂的类似HTTP的握手来建立连接，并要求通过它们传输的数据以非常特殊的方式进行编码和成帧。该协议在RFC 6455中定义。

除非你感到难以置信的自虐，否则你不想尝试自己实现。使用像Ratchet这样的库在PHP中实现WebSockets。

Answer 2

我有同样的问题兄弟，但不需要使用Ratchet或其他库，你可以编写自己的简单代码。握手过程和消息的屏蔽消除是相当困难的，所以我复制了那些

的代码

function perform_handshaking($receved_header,$client_conn, $host, $port)
{
    $headers = array();
    $lines = preg_split("/\r\n/", $receved_header);
    foreach($lines as $line)
    {
        $line = chop($line);
        if(preg_match('/\A(\S+): (.*)\z/', $line, $matches))
        {
            $headers[$matches[1]] = $matches[2];
        }
    }

    $secKey = $headers['Sec-WebSocket-Key'];
    $secAccept = base64_encode(pack('H*', sha1($secKey . '258EAFA5-E914-47DA-95CA-C5AB0DC85B11')));
    //hand shaking header
    $upgrade  = "HTTP/1.1 101 Web Socket Protocol Handshake\r\n" .
    "Upgrade: websocket\r\n" .
    "Connection: Upgrade\r\n" .
    "WebSocket-Origin: $host\r\n" .
    "WebSocket-Location: ws://$host:$port/\r\n".
    "Sec-WebSocket-Accept:$secAccept\r\n\r\n";
    socket_write($client_conn,$upgrade,strlen($upgrade));
    return $upgrade;
}

function unmask($text) {
    $length = ord($text[1]) & 127;
    if($length == 126) {
        $masks = substr($text, 4, 4);
        $data = substr($text, 8);
    }
    elseif($length == 127) {
        $masks = substr($text, 10, 4);
        $data = substr($text, 14);
    }
    else {
        $masks = substr($text, 2, 4);
        $data = substr($text, 6);
    }
    $text = "";
    for ($i = 0; $i < strlen($data); ++$i) {
        $text .= $data[$i] ^ $masks[$i%4];
    }
    return $text;
}

//Encode message for transfer to client.
function mask($text)
{
    $b1 = 0x80 | (0x1 & 0x0f);
    $length = strlen($text);

    if($length <= 125)
        $header = pack('CC', $b1, $length);
    elseif($length > 125 && $length < 65536)
        $header = pack('CCn', $b1, 126, $length);
    elseif($length >= 65536)
        $header = pack('CCNN', $b1, 127, $length);
    return $header.$text;
}

而不是socket_accept用户socket_read来获取包含来自网页的请求的http头，它想要将其http conn升级为websocket，然后使用上面的握手函数编写一个接受头消息。然后你的连接将被建立。但仍然在客户端你必须添加像这样的事件

if("WebSocket" in window){
    var a = "ws://"+serverip+":9000";
    var ws = new WebSocket(a);
    var error = null;

    ws.onopen = function(){
        open();
    }

    ws.onerror = function(err){
        errorhandler(err);

    }
    ws.onmessage = function(e){
        messagehandler(e);

    }
    ws.onclose = function(){
        close();
    }

}

function  open(){
               document.getElementById('logs').innerHTML+='<p>WebSocket Connection OPened</p>';

}

function errorhandler(err){
               document.getElementById('logs').innerHTML+='<p>WebSocket Connection Error occured &nbsp'+err.data+'</p>';

}

function messagehandler(a){
               document.getElementById('logs').innerHTML+="<p>"+a.data+"</p>";

}

function close(){
                document.getElementById('logs').innerHTML+='<p>WebSocket Connection Closed</p>';
                ws = null;

}

创建PHP websockets服务器

2 个答案: