Question

这是形成服务器期望的JSON的代码。但是存在一些问题

<!DOCTYPE html>
<html>
<body>
<script language="javascript" type="text/javascript">
<!--
//var acc = {};
var x = 10;
var y = 20;
var z = 30;



var output = [];
output[0] = {
    name: "Accelerometer_X",
    value: JSON.parse(x), // retrieve x
};
output[1] = {
    name: "Accelerometer_Y",
    value: JSON.parse(y), // retrieve y
};
output[2] = {
    name: "Accelerometer_Z",
    value: JSON.parse(z) // retrieve z
};

var record = [];
record[0] = {
    starttime: new Date(),
    output: output,
};

var observations = [];
observations[0] = {
    sensor: "",
    record: record,
};

var fromData = {};
fromData.version = "1.0.1";
fromData.observations = observations;
alert(JSON.stringify(fromData));
console.log(JSON.stringify(fromData));
//-->
</script>
</body>
</html>

输出JSON是：

{
    "version": "1.0.1",
    "observations": [
        {
            "sensor": "",
            "record": [
                {
                    "starttime": "2014-08-15T16:01:34.711Z",
                    "output": [
                        {
                            "name": "Accelerometer_X",
                            "value": 10
                        },
                        {
                            "name": "Accelerometer_Y",
                            "value": 20
                        },
                        {
                            "name": "Accelerometer_Z",
                            "value": 30
                        }
                    ]
                }
            ]
        }
    ]
}

但是预期的JSON是：

{
    "version": "1.0.1",
    "observations": [
        {
            "sensor": "",
            "record": [
                {
                    "starttime": "1-JAN-2014 15:30:00 IST",
                    "output": [
                        {
                            "name": "Accelerometer_X",
                            "value": "10"
                        },
                        {
                            "name": "Accelerometer_Y",
                            "value": "20"
                        },
                        {
                            "name": "Accelerometer_Z",
                            "value": "30"
                        }
                    ]
                }
            ]
        }
    ]
}

预期JSON中的值在＆＃34;＆＃34;即

                    {
                        "name": "Accelerometer_Z",
                        "value": "30"
                    }

但是制作的JSON是：

                    {
                        "name": "Accelerometer_Z",
                        "value": 30
                    }

另一个问题是启动时间。预期的启动时间格式为

1-JAN-2014 15:30:00 IST

产生的开始时间是：

2014-08-15T16:01:34.711Z

我不知道如何改变这一点。请帮帮我。

Answer 1

您不应对要放在对象中的值使用JSON.parse。 JSON.parse方法用于将JSON字符串解析为对象，但值不是JSON字符串。

删除JSON.parse调用（因为它不会更改值），并使用toString方法将值转换为字符串：

output[0] = {
    name: "Accelerometer_X",
    value: x.toString(),
};
output[1] = {
    name: "Accelerometer_Y",
    value: y.toString(),
};
output[2] = {
    name: "Accelerometer_Z",
    value: z.toString()
};

没有用于格式化日期的功能构建，您需要自己创建。类似的东西：

function formatDate(d) {
  return d.getDate() + '-' + (d.getMonth() + 1) + "-" + d.getFullYear() + " " + d.getHours() + ":" + d.getMinutes() + ":" + d.getSeconds() + " IST";
}

用法：

record[0] = {
    starttime: formatDate(new Date()),
    output: output,
};

Answer 2

这是迄今为止的代码：

<!DOCTYPE html>
<html>
<body>
<script language="javascript" type="text/javascript">
<!--
//var acc = {};
var x = 10;
var y = 20;
var z = 30;

//var accString = JSON.stringify(acc); // that's what you have

var output = [];
output[0] = {
    name: "Accelerometer_X",
    value: x.toString(), // retrieve x
};
output[1] = {
    name: "Accelerometer_Y",
    value: y.toString(), // retrieve y
};
output[2] = {
    name: "Accelerometer_Z",
    value: z.toString() // retrieve z
};

var record = [];
record[0] = {
    starttime: new Date(),
    output: output,
};

var observations = [];
observations[0] = {
    sensor: "",
    record: record,
};

var fromData = {};
fromData.version = "1.0.1";
fromData.observations = observations;
alert(JSON.stringify(fromData));
console.log(JSON.stringify(fromData));
//-->
</script>
</body>
</html>

但现在时间仍然存在问题。有人解决这个问题吗？

JSON形成的困难

2 个答案: