Question

我遇到了问题而我找不到错误。它不允许我更新我的索引并总是说SQL error or missing data type near WHERE syntax。其他一切都有效。所以我认为你们可以看看这个：

Create Table: execute("CREATE TABLE Players (player TEXT, money DOUBLE, job TEXT, level INTEGER, exp DOUBLE)"); 作品

Insert: DATABASE.execute("INSERT INTO Players VALUES ('" + player + "', " + money + ", '" + job.getJob() + "', " + job.getLevel() + ", " + job.getEXP() + ")"); 作品

Update: DATABASE.execute("UPDATE Players WHERE player = '" + player.toLowerCase() + "' SET money = " + money + ", job = '" + job.getJob() + "', level = " + job.getLevel() + ", exp = " + job.getEXP()); 无效

我使用以下值进行更新：

player = gemaken
money = 100.0
job.getJob() = miner
level = 0
exp = 0.0

提前致谢！

此致 Gemaken

Answer 1

在SQL UPDATE中，SET部分首先出现，WHERE部分出现在后面：

DATABASE.execute("UPDATE Players SET money = " + money + ", job = '" + job.getJob() + "', level = " + job.getLevel() + ", exp = " + job.getEXP()) + " WHERE player = '" + player.toLowerCase() + "';

另外，请考虑使用参数和预处理语句。

Answer 2

请尝试这个

Update: DATABASE.execute("UPDATE Players SET money = " + money + ", job = '" + job.getJob() + "', level = " + job.getLevel() + ", exp = " + job.getEXP() WHERE player = '" + player.toLowerCase());

Answer 3

更新查询提供错误的原因是UPDATE查询的语法不正确。请遵循here或here

中的语法

您的查询应如下所示：

DATABASE.execute("UPDATE Players SET money=" + money + ", job='" + job.getJob() + "', level=" + job.getLevel() + ", exp=" + job.getEXP() + " WHERE player='" + player.toLowerCase() + "'")

尝试更新SQLite时“SQL错误或WHERE语法附近缺少数据类型”

3 个答案: