Question

这是我的程序，我得到错误作为非法表达的开始我必须为此错误做些什么所有这些错误都在public void doGet

    import javax.servlet.*;
    import javax.servlet.annotation.*;
    import javax.servlet.http.*;
    import java.io.*;
    import java.sql.*;
    @WebServlet("/emps")
    public class EmpServlet extends HttpServlet
    {
        private Connection cn;
        public void init()
        {
            try
            {
                Class.forName("oracle.jdbc.driver.OracleDriver");
                cn=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe","kumar","tiger");
            }
            catch(Exception k)
            {
                k.printStackTrace();
            }

        public void doGet(HttpServletRequest req,HttpServletResponse res) throws ServletException,IOException
// iam getting error in this place only.
        {
            int eno=Integer.parseInt(req.getParameter("t1"));
            PrintWriter out=res.getWriter();
            try
            {
                PreparedStatement ps=cn.prepareStatement("select * from emp1 where empno=?");
                ps.setInt(1,eno);
                ResultSet rs=ps.executeQuery();
                if(rs.next())
                {

                    out.println("<body bgcolor=cyan>");
                    out.println("<a href=http:localhost:8081/webapp/salarys?e="+eno+">DisplayServlet</a>");
                }
                else
                {
                    RequestDispatcher rd=req.getRequestDispatcher("emp.html");
                    rd.include(req,res);
                    out.println("Invalid employee");
                }
            }
            catch(Exception r)
            {
                r.printStackTrace();

        }//here is  the another error pharsing
    }

我收到11个错误请帮我做什么？

Answer 1

您忘记了}末尾的结束init()。

如果您要正确缩进代码，错误就会一目了然。

Answer 2

您的init（）方法未关闭

这是我的程序，我得到错误作为非法开始表达我必须为此错误做什么

2 个答案: