对于Java来说,我是业余爱好者。我需要使用java程序来制作RSA公钥。我有一个想要密钥的perosn给我的脚本,它看起来像这样:
import java.io.IOException;
import java.math.BigInteger;
import java.security.GeneralSecurityException;
import java.security.Key;
import java.security.KeyFactory;
import java.security.KeyPair;
import java.security.KeyPairGenerator;
import java.security.NoSuchAlgorithmException;
import java.security.NoSuchProviderException;
import java.security.Provider;
import java.security.SecureRandom;
import java.security.Security;
import java.security.interfaces.RSAPrivateKey;
import java.security.interfaces.RSAPublicKey;
import java.security.spec.RSAPrivateKeySpec;
import java.security.spec.RSAPublicKeySpec;
import java.util.HashMap;
import java.util.Map;
import javax.crypto.Cipher;
import javax.crypto.KeyGenerator;
public class CustomRSAKeyPairGenerator{
public void generate() {
try {
KeyPairGenerator objlRSAKeyPairGen =
KeyPairGenerator.getInstance("RSA");
objlRSAKeyPairGen.initialize(2048);
KeyPair objlRSAKeyPair = objlRSAKeyPairGen.generateKeyPair();
RSAPublicKey objlPublicKey = (RSAPublicKey) objlRSAKeyPair.getPublic();
RSAPrivateKey objlPrivateKey = (RSAPrivateKey) objlRSAKeyPair.getPrivate();
StringBuffer strblPublicKey = new StringBuffer();
strblPublicKey.append(objlPublicKey.getModulus().toString(16).toUpperCase());
strblPublicKey.append('~');
strblPublicKey.append(objlPublicKey.getPublicExponent().toString(16).toUpperCase()
);
System.out.println(strblPublicKey.toString());
StringBuffer strblPrivateKey = new StringBuffer();
strblPrivateKey.append(objlPrivateKey.getModulus().toString(16).toUpperCase());
strblPrivateKey.append('~');
strblPrivateKey.append(objlPrivateKey.getPrivateExponent().toString(16).toUpperCase());
System.out.println(strblPrivateKey.toString());
}catch (NoSuchAlgorithmException noSuchAlgrtm){
System.out.println(noSuchAlgrtm.getMessage());
}catch (NoSuchProviderException noSuchProvdr) {
System.out.println((noSuchProvdr.getMessage());
}
}
}
但是当我跑步时,我得到了:
CustomRSAKeyPairGenerator.java:51:')'预期 的System.out.println((noSuchProvdr.getMessage()); ^ 1错误
我不明白这里的问题。我对java很熟悉,接下来该怎么办?这只是一个错字吗?
答案 0 :(得分:1)
问题出在代码底线的第4位:
System.out.println((noSuchProvdr.getMessage());
^
从那里删除额外的括号以使其成为
System.out.println(noSuchProvdr.getMessage());
修改:如果编译器告诉您java.security.NoSuchProviderException is never thrown in body of corresponding try statement
,请删除最后catch
块
catch (NoSuchProviderException noSuchProvdr) {
System.out.println((noSuchProvdr.getMessage());
}
答案 1 :(得分:0)
计算那条线上的parens。