显示最后一个条纹

Question

我有一张桌子

ID  HomeTeam     AwayTeam     FTHG  FTAG    WDL
1   Anderlecht   Lokeren      2     3       W
2   Lokeren      Bergen       2     1       W
3   Kortrijk     Lokeren      3     3       D
4   Oud-Heverlee Lokeren      2     1       L
5   Lokeren      Oostende     1     0       W
6   Charleroi    Lokeren      2     1       L
7   Lokeren      Gent         2     2       D
8   Club Brugge  Lokeren      1     0       L
9   Lokeren      Mechelen     4     0       W
10  Lokeren      Club Brugge  0     3       L

我喜欢算上Lokeren的最后一连胜

例如，上一场比赛洛克伦失去了结果应该看起来像这样

team        wdl       count
Lokeren      L          1 

Answer 1

这个答案假定您使用sql server 2012（2008年对分析功能的支持较低）。

with sub as
 (select x.*,
         row_number() over(partition by wdl order by id) - row_number() over(order by id) as grp
    from (select id, hometeam as team, wdl
            from tbl
           where hometeam = 'Lokeren'
          union all
          select id,
                 awayteam,
                 case when wdl = 'W' then 'L' else 'W' end
            from tbl
           where awayteam = 'Lokeren') x)
select team, wdl, count(*) as count
  from sub
 where grp = (select grp from sub where id = (select max(id) from sub))
 group by team, wdl

您可以在此处看到小提琴演示：http://sqlfiddle.com/#!6/bc4d7/4/0

为了测试目的，我添加了第11局，他们也输了。