Question

我从数据库中获取数据。我有两个表是关系表。我正在使用sql JOIN来获取所需的信息。现在我有多个数组，其中包含数据。但现在我想组合具有相同ID（team_id）的数组，然后在页面上回显它。或者我的意思是组合具有相同ID（team_id）的数组，我可以为每个团队正确地对它们进行排序。

这是我的数组来自我的数据库。可以有无数个团队名称（数组）。

Array
(
    [points_1] => 2
    [0] => 2
    [points_2] => 10
    [1] => 10
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 7
    [0] => 7
    [points_2] => 10
    [1] => 10
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 10
    [0] => 10
    [points_2] => 10
    [1] => 10
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 4
    [0] => 4
    [points_2] => 15
    [1] => 15
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 14
    [0] => 14
    [points_2] => 14
    [1] => 14
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 22
    [0] => 22
    [points_2] => 22
    [1] => 22
    [name] => Team 1
    [2] => Team 1
    [team_id] => 1
    [3] => 1
)
Array
(
    [points_1] => 1
    [0] => 1
    [points_2] => 10
    [1] => 10
    [name] => Team 2
    [2] => Team 2
    [team_id] => 3
    [3] => 3
)
Array
(
    [points_1] => 10
    [0] => 10
    [points_2] => 10
    [1] => 10
    [name] => Team 3
    [2] => Team 3
    [team_id] => 6
    [3] => 6
)

这是我的Foreach / JOIN代码：

echo "<pre>";
    foreach ($db->query("SELECT points_1, points_2, name, team_id FROM points INNER JOIN teams ON teams.id=points.team_id ORDER BY team_id ASC") as $result) {
        print_r($result);

    }

我想通过所有数组并整齐地回应它们并按照图片中的顺序排序。

enter image description here

Answer 1

如果输出就像这个数组（你可以设置你需要的键）

$arr = array(
array('name' => 'Team 1','points_1' => 2,'points_2' => 10),
array('name' => 'Team 1','points_1' => 7,'points_2' => 10),
array('name' => 'Team 2','points_1' => 1,'points_2' => 12),
array('name' => 'Team 3','points_1' => 4,'points_2' => 32),
array('name' => 'Team 2','points_1' => 1,'points_2' => 16),
);

然后尝试：

$arrayTotals = array();


foreach ($arr as $result) {
        //print_r($result);

        $arrayTotals[$result['name']][] = array('points_1'=>$result['points_1'],'points_2'=>$result['points_2']);

}

var_dump($arrayTotals);

foreach($arrayTotals as $team=>$values){
    echo '<div style="float:left;">'.$team;
    $sum1=0;
    $sum2=0;
    foreach($values as $v){
        echo '<br />'.$v['points_1'].'/'.$v['points_2'];
        $sum1 +=$v['points_1'];
        $sum2 +=$v['points_2'];
    }
    echo '<br />Total:'.$sum1.'/'.$sum2;
    echo '</div>';
}

组合具有相同ID的数组

1 个答案: