Question

在Spring Controller中，我配置了一个全局异常处理程序。我使用Spring Controller PathVarilable的自定义类型（IP地址类型）。当Spring将传入的String转换为IpAddress类型时，将引发验证异常（自定义）。但是Spring忽略了异常并抛出了它自己的TypeMismatchException，错误代码为400。我想用自己的错误代码抛出自己的异常。有没有办法覆盖这种行为？我尝试从全局异常处理程序中抛出自定义异常，但Spring仍然覆盖它。

Answer 1

@ControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {

    public RestResponseEntityExceptionHandler() {
        super();
    }

    // API

    // 400

    /**
     * 自定义类型转换错误
     */
    @Override
    protected ResponseEntity<Object> handleTypeMismatch(TypeMismatchException ex, HttpHeaders headers,
			HttpStatus status, WebRequest request) {
    	
    	
    	if (!(request.getHeader("accept").indexOf("application/json") > -1 || (request
				.getHeader("X-Requested-With")!= null && request
				.getHeader("X-Requested-With").indexOf("XMLHttpRequest") > -1))) {
			// 如果不是异步请求
			// Apply HTTP status code for error views, if specified.
			// Only apply it if we're processing a top-level request.
            final String bodyOfResponse = "Illegal Arguments";
            return handleExceptionInternal(ex, bodyOfResponse, headers, status, request);
		} else {// JSON格式返回
            Map<String,Object> bodyOfResponse = new HashMap<String,Object>();
    	    bodyOfResponse.put("message", "Illegal Arguments");
    	    bodyOfResponse.put("code",400);
            return handleExceptionInternal(ex, bodyOfResponse, headers, status, request);
		}
	}
}

Spring Framework：忽略TypeMismatchException

1 个答案: