Question

这是我的代码，我必须创建它才允许

用户输入三角形的三边长度，如Length1，Length2和Length3
如果任何双方的长度相同，则程序输出“Isosceles”
否则程序会输出“Not isosceles”

然而，输出部分似乎不起作用。我是这类编码的新手，请帮帮忙？

Length1 = raw_input()
Length2 = raw_input()
Length3 = raw_input()

print Length1
print Length2
print Length3
print Length1 == Length2
print Length2 == Length3
print Length1 == Length3

if Length1 == Length2 is True:
    print "Isosceles"
else: 
    print "Not Isosceles"  

if Length2 == Length3 is True:
    print "Isosceles"
else:
    print "Not Isosceles"

if Length1 == Length3 is True:
    print "Isosceles"
else:
    print "Not Isosceles"

Answer 1

问题在于Python解释

if Length1 == Length2 is True:

像

if Length1 == Length2 and Length2 is True:

Comparison operators, like <, ==, or is are chained.这对例如非常有用。 a < b < c，但它也可能导致一些意外行为，如您的情况。

将这些支票更改为

if (Length1 == Length2) is True:

或更好，只需使用

if Length1 == Length2:

或者，您可以使用set计算不同方的数量：

distinct_sides = len(set([Length1, Length2, Length3]))
if distinct_sides == 1:
    print "Equilateral"
if distinct_sides == 2:
    print "Isosceles"
if distinct_sides == 3:
    print "Scalene"

Answer 2

我只会创建一个函数来检查每一对是否相等

def isosceles(x1, x2, x3):
    return x1 == x2 or x2 == x3 or x1 == x3

# slightly faster version since it returns after the first True
def isosceles(x1, x2, x3):
    return any(x1 == x2, x2 == x3, x1 == x3)

确保您将输入转换为int，这样您就不会比较string值

Length1 = int(raw_input())
Length2 = int(raw_input())
Length3 = int(raw_input())

然后调用你的函数

if isosceles(Length1, Length2, Length3):
    print "Isosceles"
else:
    print "Not isosceles"

Answer 3

if Length1 == Length2: # don't use `if Length1 == Length2 is True:`
    print "Isosceles"

elif Length2 == Length3:
    print "Isosceles"

elif Length1 == Length3:
    print "Isosceles"
else:
    print "Not Isosceles"

您需要使用elif，elif's仅在前一个语句为False时进行评估，始终评估if's。

if Length1 == Length2 is True:与if Length1 == Length2不同：

如果Length1和Length2 = True都是{{1}}，那么您的陈述只会为真。

if-else，在python上使用True和False语句。 skulpt.org

3 个答案: