Question

我需要帮助我如何使用命令行参数打开以下两个文本文件，answerfile和outputfile：

    int counter = 0;
    string line;

    // Read the file and display it line by line.
    System.IO.StreamReader file = new System.IO.StreamReader(@"c:\AnswerFile.txt");
    System.IO.StreamWriter fileWriter = new System.IO.StreamWriter(@"C:\outputFile.txt");

    while ((line = file.ReadLine()) != null)
    {
        System.Console.WriteLine(line);
        fileWriter.WriteLine(line);
        counter++;
    }

    file.Close();
    fileWriter.Close();
    System.Console.WriteLine("There were {0} lines.", counter);
    // Suspend the screen.
    System.Console.ReadLine();

任何帮助表示赞赏！谢谢

Answer 1

这将是

System.IO.StreamReader file = new System.IO.StreamReader(args[0]);
System.IO.StreamWriter fileWriter = new System.IO.StreamWriter(args[1]);

或者如果主要功能上没有string[] args，那么

var args = Environment.GetCommandLineArgs();

假设您的程序名为prog.exe

并以C:\>prog.exe infile.txt outfile.txt

开头

Answer 2

在代码的这两行中尝试以下更改将是相同的。

//System.IO.StreamReader file = new System.IO.StreamReader(@"c:\AnswerFile.txt");
//System.IO.StreamWriter fileWriter = new System.IO.StreamWriter(@"C:\outputFile.txt");

if (args.Length < 2)
{
    throw new Exception("File(s) not provided.");
}

System.IO.StreamReader file = new System.IO.StreamReader(args[0]);
System.IO.StreamWriter fileWriter = new System.IO.StreamWriter(args[1]);

Answer 3

编译代码（考虑它创建一个文件说demo.exe）。现在打开命令提示符并转到demo.exe存在的位置。放下以下的commad。

demo.exe "c:\AnswerFile.txt" "C:\outputFile.txt"

希望它能奏效。

两个文本文件的命令行参数

3 个答案: