Question

我被困在调用存储在oracle中的过程并从Hibernate客户端返回选定的列。

employee3.hbm.xml

        <hibernate-mapping>
          <class name="Employee" table="employee3">
            <id name="eid" column="eid"/>
      <property name="fname" column="first_name"/>
      <property name="lname" column="last_name"/>
      <property name="email" column="email"/>
   </class>


<sql-query name="test1" callable="true">
  <return  alias ="test1" class ="Employee">
    <return-property name="fname" column="first_name"/>
    <return-property name="lname" column="last_name"/>
</return>
  {?=call get_empdetails_assg(?,?)}
</sql-query>
</hibernate-mapping>

testClient.java

Session ses =sf.openSession();

Transaction tx = ses.beginTransaction();
System.out.println("--------------got tx object-----------");
Employee eb =null;

SQLQuery q1=(SQLQuery)ses.createSQLQuery("test1");


System.out.println("--------------q1 processing-----------");
q1.setString(0,"v%");

存储过程：

create or replace  procedure get_empdetails_assg(mycursor out sys_refcursor,cond in           varchar)

as 
begin
open mycursor for

select eb.first_name,eb.last_name from employee3 eb where eb.first_name like cond;

end;

我在尝试使用setString（0，“v％”）在sql中设置cond时出现输出错误

--------------q1 processing-----------                                          Exception in thread "main" java.lang.IllegalArgumentException: No positional parameters in query: test1                                                                 at org.hibernate.internal.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:442)

请任何输入..厌倦了尝试:(

此致杰

Answer 1

您没有正确传递参数，您需要拨打getNamedQuery()，而不是createSQLQuery()。

试试这个。

Query query = session.getNamedQuery("test1");
query.setParameter(1, "some_vlaue");
query.setParameter(2, "some_vlaue");
List result = query.list();

从hbm调用存储过程

1 个答案: