我可以使用org-mode生成以下表格,
Day 1 | a) A |
| b) B |
| c) C |
Day 2 | a) D |
Day 3 | a) E |
答案 0 :(得分:0)
喜欢这个吗?
|-----------+------|
| Monday | a) A |
| | b) B |
| | c) C |
|-----------+------|
| Tuesday | a) D |
|-----------+------|
| Wednesday | a) E |
|-----------+------|
我刚进入
|||
然后在表格内 RET 获取更多行,并使用 C-RET 获取行。填写并离开。似乎导出到HTML和文本就好......
答案 1 :(得分:0)
您还可以编写一个函数,将列表的任意省略列表转换为表格。调试列表列表(将“表”字符串发送到 Messages 缓冲区)可能很有用。 像这样:
(defun list-of-lists-to-org-table (lol &optional justify min-cell-width columns) (let ((buf (get-buffer-create "*org-tb*"))) (with-current-buffer buf (erase-buffer) (mapcar (lambda (x) (mapcar (lambda (y) (insert (format "%s&" y))) x)(insert "\n")) lol) (table-capture 1 (point-max) "&" "\n" justify min-cell-width columns) (buffer-substring-no-properties (point-min) (point-max)) )))
示例输入:
(list-of-lists-to-org-table '((Abc Def "xyz") (1 1 X1) (2 4 X2) (3 9 X3) (4 16 X4)))
示例输出:
+-----+-----+-----+ |Abc |Def |xyz | +-----+-----+-----+ |1 |1 |X1 | +-----+-----+-----+ |2 |4 |X2 | +-----+-----+-----+ |3 |9 |X3 | +-----+-----+-----+ |4 |16 |X4 | +-----+-----+-----+