Question

我是C＃的新手，我正在学习反转整数（数字）。我必须使用forloop和数组来完成代码，但我真的不知道如何使用它们。例如。如果输入为：1 2 3 4 5 6 结果应为：6 5 4 3 2 1

有人可以帮助我。谢谢:)）

编辑：我真的很抱歉，我忘了添加代码。这里是。再次感谢

static void Main(string[] args)
{
    Console.WriteLine("Enter 6 Numbers");
    int numb = int.Parse(Console.ReadLine());
    int reverse = 0;
    while (numb > 0)
    {
        int rem = numb % 10;
        reverse = (reverse * 10) + rem;
        numb = numb / 10;
    }

    Console.WriteLine("The reverse is = {0}", reverse);
    Console.ReadLine();
}

Answer 1

除非您需要使用循环，否则更简单的解决方案是使用Array.Reverse：

int[] array = { 1, 2, 3, 4, 5, 6 };
Array.Reverse(array);

您可以使用for循环并迭代一半数组，使用数组另一侧的位置切换位置。

int holder = 0;
int size = array.Length;
for (int i = 0; i < size / 2; ++i)
{
    holder = array[i];
    array[i] = array[size - 1 - i];
    array[size - 1 - i] = holder;
}

Answer 2

这对我不起作用？

int[] array = new int[4];

int getlength = array.Length;

int k = getlength - 1;

array[0] = 100;
array[1] = 500;
array[2] = 700;
array[3] = 900;

for (int j = 0; j < array.Length; j++)
{

    Console.WriteLine(array[j]);

}

Console.ReadLine();

for (int i = 0; i < array.Length; i++)
{

    Console.WriteLine(k);
    Console.ReadLine();
    array[i] = array[k];
    k--;
    Console.WriteLine(array[i]);

}

Console.ReadLine();

Answer 3

这是使用循环反转数字/整数并使用Array.Reverse功能的简单逻辑

示例：输入12345将为我们提供54321

的输出

namespace PurushLogics
{
    class Purush_ReverseInteger
    {
        static void Main()
        {
            //Reverse a Number  
            int intstr;
            string intreverse = "";
            int intLength = 0;
            int? intj = null;
            Console.WriteLine("Enter a Number"); // Entering "12345" has input will return "54321" as output

            intstr = int.Parse(Console.ReadLine());//Getting integer from Console  

            char[] inta = intstr.ToString().ToCharArray();


            intLength = inta.Length - 1;
            for (int c = intLength; c >= 0; c--)
            {
                intreverse = intreverse + inta[c].ToString();
                intj = int.Parse(intreverse);
            }

            Console.WriteLine("Reverse Number is \"{0}\"", intj);//Displaying the reverse integer  
            Console.ReadLine();

            //Reverse integer using Array.Reverse
            Array.Reverse(inta);
            foreach (char reverse in inta)
            {
                Console.Write(reverse);
            }
            Console.ReadLine();
        }
    }
}

Answer 4

static void Main(string[] args)
        {
            int[] numbers = new int[6];
            for (int i = 0; i < 6; i++)
            {
                Console.Write("Number {0} : ", i + 1);
                numbers[i] = Convert.ToInt32(Console.ReadLine());
            }
            Console.WriteLine();
            for (int i = 5; i >= 0; i--)
            {
                Console.Write("{0} ", numbers[i]);

            }

            Console.ReadLine();
        }

Answer 5

   class Program
{
    static void Main(string[] args)
    {
        int[] array = new int[] { 1, 2, 3, 4, 5, 6,7};
        int temp = 0;
        for (int i = array.Length - 1; i >= (((array.Length - 1) % 2==0)? (((array.Length - 1) / 2)):((array.Length - 1) / 2)+1) ; i--)
        {
            temp = array[(array.Length - 1) - i];
            array[(array.Length - 1) - i] = array[i];
            array[i] = temp;
        }

        foreach (var p in array)
        {
            Console.WriteLine(p);
        }
        Console.ReadLine();
    }
}

Answer 6

int[] numbers=new int[]{1,2,3,4,5};
    int[] reverse=new int[numbers.Length];
    int j=numbers.Length-1;
    for(int i=0;i<numbers.Length;i++)
    {

        reverse[i]=numbers[j];
        Console.WriteLine(reverse[i]);
        j--;
    }

如何使用＆＃39; for loop＆＃39;来反转整数和一个＆＃39;阵列＆＃39;在C＃中

6 个答案: