Question

表1：

Temp    ResID     Code      Date
11       1         SPR       
12       1         SPG       2009-10-05
13       1         SPR 
14       1         SPG       2011-10-08

表2：

TempID    Res ID     InDate       Out Date
21         1.         2009-10-05    2010-11-15
22         1.         2011-10-08    2011-11-09

表3 :(期望结果）

ResID     Code      Date
1         SPR       2010-11-15
1         SPG       2009-10-05
1         SPR       2011-11-09 
1         SPG       2011-10-08

我有两张桌子。

我需要为代码为SPR的每一行的每个ID更新表1 Date列。表1日期列中的SPG值等于同一驻留的

的InDate列值

请咨询查询。如何通过连接两个表（表1和表2以获取表3

）的查询来实现此目的

Answer 1

从选择语句编辑到更新

我认为这对你有用。请参阅SqlFiddle

Update
  Table1
set
  Table1.[Date] = Table2.OutDate
from
  Table1
  inner join
  (
    select
      Temp,
      ResID,
      Code,
      Date,
      row_number() over(partition by ResID order by Temp) as RowId
    from
      Table1
    where
      Code = 'SPR'
  ) as SPR on Table1.Temp = SPR.Temp
  inner join
  (
    select
      ResID,
      Code,
      Date,
      row_number() over(partition by ResID order by Temp) as RowId
    from
      Table1
    where
      Code = 'SPG'
   ) as SPG on SPG.RowId = SPR.RowId and SPG.ResID = SPR.ResID
  inner join
  Table2 on Table2.InDate = SPG.Date and Table2.ResID = SPG.ResID

Answer 2

您可以删除所有SPR行，然后生成它们：

delete  Table1
where   code = 'SPR';

insert  Table1
        (ResID, Code, [Date])
select  t1.ResID
,       'SPR'
,       OutDate
from    Table1 t1
join    Table2 t2
on      t1.ResID = t2.ResID
        and t1.[Date] = t2.InDate
where   t1.Code = 'SPG';

Example at SQL Fiddle.

Answer 3

如果table2具有每个表的值，那么你可以使用table2，有点奇怪但你可以随时加入主表以获得适当的结果，如果你想

select Convert(varchar, indate, 102) as date, 'SPG' as code, resid from table2
union all
select convert(varchar, outdate, 102) as date, 'SPR' as code, resid from table2

SQL Fiddle

根据其他日期获取日期

3 个答案: